Latest Elitmus Aptitude Question SOLUTION: . if a=bc then (a-b)^n-(c-b)^n+c^n for any value of n,the equation is always divisible (a) bc (b) b but not c always (c)c but not b always (d)non of above

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(#M40019632) ELITMUS question puzzle Keep an EYE

. if a=bc then (a-b)^n-(c-b)^n+c^n for any value of n,the equation is always divisible
(a) bc (b) b but not c always
(c)c but not b always (d)non of above

Asked In Elitmus Devanshu (10 years ago)

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sanjay  (10 years ago)

put n=1 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
put n=2 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
put n=3 then the given (a-b)^n-(c-b)^n+c^n is divisible by -> bc
for for any value of n the given expression is divisible by bc
option A

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Surya Kiran  (10 years ago)

Given (a-b)^n-(c-b)^n+c^n
For any value of "n"..put n=1
Now the question becomes (a-b)^1-(c-b)^1+c^1
>>>>a-b-c+b+c
>>>
>>>>given a=bc
>>>>bc....so,it is divisible by bc

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