Latest Elitmus Aptitude Question SOLUTION: Two circles lying in the first quadrant, touch each other externally. Both the axes makes tangents with both the circles. If the distance between the two centre of the circles is 8

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(#M40019722) ELITMUS question Keep an EYE

Two circles lying in the first quadrant, touch each other externally. Both the axes makes tangents with both the circles. If the distance between the two centre of the circles is 8 cm, find the difference in their radii

Asked In Elitmus prerana (10 years ago)

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Gourav Kumar  (10 years ago)

Ans:4(root 2)
let the radius of first circle be (R,R)
let the radius of second cirlce br(r,r)
itis because its lies on line y=x int the first quadrant.so we need to find(R-r)
accoding to distance formula;
d=(sqrroot(x2-x1)^2+(y2-y1)^2);x1=r,y1=r,x2=R,y2=R;
replacing values;
d=(sqroot(R-r)^2+(R-r)^2);here dis given as 8 int the ques;
8=(sqrrrot(2(R-r)^2)
8=root2(R-r)
so;R-r=4root(2);

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Ankit Kumar  (10 years ago)

For the condition that the axes makes tangents with both the circles their centre lies on y=x line which makes an angle 45 degree with both axes hence take a look at fig. we can get it should be 8*cos(45)=4*root(2).
i.e. 4*root(2)

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Anurag Kumar Singh  (10 years ago)

4*(2^(1/2))..

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