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"The essence of mathematics is not to make simple things complicated, but to make complicated things simple." S. Gudder "Creative mathematicians now, as in the past, are inspired by the art of mathematics rather than by any prospect of ultimate usefulness." Eric Temple Bell "Why do we believe that in all matters the odd numbers are more powerful?" Pliny the Elder, Natural History "Pure mathematics is the world's best game. It is more absorbing than chess, more of a gamble than poker, and lasts longer than Monopoly. It's free. It can be played anywhere - Archimedes did it in a bathtub." Richard J. Trudeau, Dots and Lines "A man has one hundred dollars and you leave him with two dollars. That's subtraction." Mae West "''The most incomprehensible about Mathematics is that it is comprehensible''." Kiran B. Mali "My maths book suicided because it had lots of problems in it ......" Ruchi.das |
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"If α and β are the zeros of the quadratic polynomial f(x) =ax2 +bx+c, then evaluate: a* (α ^2 / β^2) + b*( α / β + β^3 / α )"
"12,18,36,48,60,78,__,__"
"3,10,13,28,31,__"
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tcs question papers:
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(#M40002158) TCS aptitude question Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5, which are divisible by 4 if repetition of digits is allowed?
- Asked In tcs Submited By-- partha (1 year ago)
- Puzzle Status: Solved By »» Kodi
-
Is this Puzzle helpful? (29) (5)
Submit Your Solution
Similer Aptitude Questions
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(#M40000534) TCS MATHS PUZZLE Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is not allowed?
a)5^7 b)5^6 c)5^9 d)5^8
- Asked In tcs Submited By-- Karthik (2 year ago)
- Puzzle Status: Solved By »» Karthik Pandiyan
- Is this Puzzle helpful? (8) (11) Submit Your Solution
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(#M40000844) TCS MATHS PUZZLE tcs recent paper Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8 - Asked In TCS Submited By-- Yashar (2 year ago)
- Puzzle Status: Solved By »» suneil
- Is this Puzzle helpful? (8) (3) Submit Your Solution
-
(#M40001712) TCS MATHS PUZZLE 2010 question Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a) 5^7 b) 5^6 c) 5^9 d) 5^8 - Asked In tcs Submited By-- UN (1 year ago)
- Puzzle Status: Solved
- Is this Puzzle helpful? (7) (1) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right but he used 57 in place of 5^7 and 58 in place of 5^8, so we made a correction
Like manish sir answer on facbook.
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(#M40002092) TCS MATHS PUZZLE Keep an EYE
How many 9 digit numbers are possible by using digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a.5^7 b.5^6 c.5^9 d.5^8 - Asked In TCS Submited By-- sankha chowdhury (1 year ago)
- Puzzle Status: Solved By »» Moumita Ghosh
- Is this Puzzle helpful? (6) (1) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40002098) TCS MATHS PUZZLE maths Keep an EYE
How many 9 digit numbers are possible by using digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
- Asked In tcs Submited By-- Moumita Ghosh (1 year ago)
- Puzzle Status: Solved By »» surbhi mathur
- Is this Puzzle helpful? (7) (3) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40002269) TCS MATHS PUZZLE tcs Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a) 5^7 b) 5^6 c) 5^9 d) 5^8
- Asked In tcs Submited By-- manjuladevi (1 year ago)
- Puzzle Status: Solved
- Is this Puzzle helpful? (4) (1) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40002574) SELF MATHS PUZZLE Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if therepetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8
- Submited By-- aniruddha mandal (1 year ago)
- Puzzle Status: Solved
- Is this Puzzle helpful? (2) (1) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40002689) TCS MATHS PUZZLE tcs Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8
- Asked In tcs Submited By-- purvi (1 year ago)
- Puzzle Status: Solved By »» Ravi agarwal
- Is this Puzzle helpful? (2) (0) Submit Your Solution
-
(#M40002697) TCS MATHS PUZZLE tcs Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8 - Asked In tcs Submited By-- UN (1 year ago)
- Puzzle Status: Solved
- Is this Puzzle helpful? (2) (0) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40002828) TCS MATHS PUZZLE tcs Keep an EYE
How many 9 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if the repetition is allowed?
a)5^7 b)5^6 c)5^9 d)5^8 - Asked In tcs Submited By-- purvi (1 year ago)
- Puzzle Status: Solved By »» Akash
- Is this Puzzle helpful? (2) (0) Submit Your Solution
Digits that can be used = 1, 2, 3, 4 and 5
For a number to divisible by 4, the last two digits have to be divisible by 4
So, the units digit cannot be 1, 3 or 5
If the units digit is 2, only 12, 32 adn 52 are acceptable as the last two digits
If the units digit is 4, only 24 and 44 are acceptable as the last two digits.
So, total 5 cases 12,24,32,44,52 are possible for the last two digits.
Now, the first 7 digits of the 9 digit number can be filled in 5^7 ways as each place can be filled by 1, 2, 3, 4 or 5.
So, desired answer = 5^7*5 = 5^8
This answer is given by Amitesh kumar and is right
Like manish sir answer on facbook.
-
(#M40003434) TCS MATHS PUZZLE Keep an EYE
How many 9 digit numbers are possible by using 1,2,3,4,5 which are divisible by 4, if the repetition is allowed
- Asked In tcs Submited By-- UN (1 year ago)
- Puzzle Status: Solved By »» Atul
- Is this Puzzle helpful? (4) (0) Submit Your Solution