Latest TCS Aptitude Question SOLUTION: 2 years ago of A is x times that of B. 3 Years hence the age of A is 4/3 times of B. What is the present age of B in binary form?

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2 years ago of A is x times that of B. 3 Years hence the age of A is 4/3 times of B. What is the present age of B in binary form?

Asked In TCS Subhankar Mondal (12 years ago)

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karan29  (12 years ago)

let age of A be a and age of B be b.
a-2=x*b--1st eq.
a+3=4/3b--2nd eq.
so (2nd eq)-(1st eq):
5=(4/3-x)*b---3rd eq.
here we can see that 5 is a prime no.
so b shud be 5 becoz if we will take (4/3-x)=5 then x will be negative which is not possible.
so b=5yrs.
x=1/3
a=11/3 yrs.
now changing 5 in binary it will be 101.
so age of b in binary is 101.

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Jayatu Bhowmick  (12 years ago)

x would be supplied

2 years ago A=xB----(1)
after 5 years(2+3) age will be
=> 5+A=4/3(xB+5)------(2)
we substitute A in eq2
=>15+3xB=4xB+20
=>xB=5
=>B=5/x

Binary value of 5/x is the ans

Is this solution Helpfull? Yes (8) | No (10)  

geetha  (12 years ago)

A-2=XB-->1,
3+A=4/3B-->2,
slove 2eq,
get A=4B-9/3
sub.to 1eq,
got B=15
binary form=1111

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