Latest GRE Aptitude Question SOLUTION: summation from i=0 to 6409 of ai=? where: ai= 29(if ai is divided by 13 & 17) ai= 17(if ai is divided by 13 & 29) ai= 13(if ai is divided by 17 & 29) ai=0(else)

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(#M40022903) GRE Numerical Ability question Keep an EYE

summation from i=0 to 6409 of ai=? where:
ai= 29(if ai is divided by 13 & 17)
ai= 17(if ai is divided by 13 & 29)
ai= 13(if ai is divided by 17 & 29)
ai=0(else)

Asked In GRE amit (10 years ago)

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ravi chandra singh  (10 years ago)

divided by 13 & 17 then:-
221(1,2,3,.............,29)
so, total no is 29 then sum=29*29=841
divided by 13 & 29 then :-
377(1,2,3,..............,17)
so, total no is 17 then sum=17*17=289
divided by 17 & 29 then:-
493(1,2,3,..............,13)
so, total no is 13 then sum=13*13=169


so, total sum=841+289+169=1299

Is this solution Helpfull? Yes (2) | No (1)  

Priyansh  (7 years ago)

For 6409 it is 6409=29*13*17
For 1 less than 6409 i.e. 6408=(29*28)+(13*12)+(17*16)=1240 ANS.

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