Latest TCS Aptitude Question SOLUTION: Find the remainder when 32^33^34 is devided by 11.

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(#M40024553) TCS question Keep an EYE

Find the remainder when 32^33^34 is devided by 11.

Asked In TCS nikhil pande (10 years ago)

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Abhishek Saxena  (10 years ago)

we can use remainder theorem when consecutive no. are there...so here we cosider it as 32*33*34 but as 33 divisible its not required so 32*34 so taking -ve and +ve remainder i.e. (-1)*(1) = -1 now the remainder is
11-1 = 10.(bcoz when the remainder is -ve we subtract it from no. dividing) so ans is 10.

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Priya Sirohi  (10 years ago)

32^33^34 = 32^1122
32^1122/11 by using remainder theorem ans will be 1

Is this solution Helpfull? Yes (11) | No (5)  

sandy  (10 years ago)

@ RUDRA
ans is 10
use remainder theorem man
(32^33^34)11(when consecutive such as 51*52*53 or 22*23*24 num are qiven)
take them as product (32*33*34)/11
as 33 is divisible by 11 leave it...
32 when divided by 11 leaves remainder -1(negative remainder)
similarly 34 when divided by 11 leaves remainder 1(+ve remainder)
(-1*1)/11 = -1/11
as we got negative term in numerator subtract it from denominator
so remainder = 11-1=10
(if you got positive term in numerator then leave it....it will be the remainder)

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rohin  (10 years ago)

(32^33^34)/11=(-1^33^34)...33^34 is always odd so -1...ie -1+11=10...so remainder is 10

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juhe rawat  (10 years ago)

use remainder therorm
since 33 is divisible by 11 remainder is 0
32 is divided by 11 =-1
33 divided by 11= 1
1*(-1)=-1
11-1=10(since the remainder is -ve)
so ans-10

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sarita kumari  (10 years ago)

remainder is 1.

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raswitha  (10 years ago)

(33-1)^33^34/11
from reminder theorem
1^33^34/11=1

Is this solution Helpfull? Yes (1) | No (1)  

richa ahuja  (10 years ago)

32^33^34/11=10^33^34/11=(-1)^33^34/11=1/11
thus remainder is 1

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Rudra  (10 years ago)

@SARIKA plzzzz explain in detail........

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