Latest TCS Aptitude Question SOLUTION: Three sides of a triangle PQ, QR, and RP contains 5, 6 and 3 points respectively. What is the max number of triangles can be made using these points.

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Three sides of a triangle PQ, QR, and RP contains 5, 6 and 3 points respectively. What is the max number of triangles can be made using these points.

Asked In TCS nikhil pande (10 years ago)

Solved SWETA YADAV Read Solution (11)

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Read Solution (11) :

SWETA YADAV  (10 years ago)

answer is 333.
here there are 5+6+3 =14 points from which triangle can be made. there for number of triangles made out of it is 14C3.
but as triangle cannot be made out of collinear points therefore total number of triangle would be
14C3-3C3-6C3-5C3
=333.

Is this solution Helpfull? Yes (80) | No   

ramya  (10 years ago)

given triangle sides have 5,6,3 points
now total we have 14 points.in that to form a triangle we need 3 points
so we have total of 14c3 triangles.but there are also 5,6,3 collinear points from which we cant form a triangle.

so the total triangles are 14c3-(5c3+6c3+3c3)=333

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neha priya  (10 years ago)

(14!/(3!*11!))-(5!/(2!*3!)+6!/(3!*3!)+3c3)=333.
ans is 333.

Is this solution Helpfull? Yes (3) | No (1)  

jayant narwani  (10 years ago)

all points on same line are colinear so they cannot contribute in formation of a triangle. no of triangles that can be formed will be 6*5*3

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Pihu  (10 years ago)

yes i think Sweta is correct.

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diwakar kumar singh  (10 years ago)

12c3/ 5!*6!*3!
12 total pts with 5, 6 and 3 pts gettin collinear

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MD.MOJAFFAR ANSARI  (10 years ago)

=(14!/3!*11!)-4-5-2

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Pihu  (10 years ago)

ans is 6*5*3=90

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kalyani dangeti  (10 years ago)

Doubt !! @Sweta yadav
If we take pq,qr,rp as lines then joining 2 points of any 2 sides forms triangle.
then 63(6*5+3*6+3*5) extra triangles.
Then ans is 333+63 =396

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sandya  (10 years ago)

s manoj is crct

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Guru Pranav  (10 years ago)

Total 333 triangles will be made !!!

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