Latest self Aptitude Question SOLUTION: Consider a two digit number x and and another number y with x's digits reversed which of the following cannot be x+y, indicate all that apply? option a) 121 b) 220 c) 111 d) 110

• Placement Papers
• /
• self

self Question Papers:

(#M40024577) SELF question Keep an EYE

Consider a two digit number x and and another number y with x's digits reversed which of the following cannot be x+y, indicate all that apply?
option
a) 121
b) 220
c) 111
d) 110
e) 187

Madhu pericherla (10 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (1)   (1) Submit Your Solution

Read Solution (3) :

Rahul Gupta  (10 years ago)

ANS: 111
Let x be 10a+b
Then digits reversed will produce y= 10b+a
So sum of these two numbers=x+y= 11a+11b=11(a+b)
So the new number formed must be divisible by 11
Among the given numbers, 111 is the only one which is not divisible by 11 hence, it cannot be x+y

Is this solution Helpfull? Yes (8) | No   

Devendra Marghade  (10 years ago)

111
If a & b are the digits of tens & unit place respectively,then
First number,x=10a+b and y=10b+a
So x+y=(10a+b)+(10b+a)=11(a+b)
So number multiple of 11 can be a sum of x & y, except 111

Is this solution Helpfull? Yes (3) | No   

vasudhasrichaitanya  (10 years ago)

@Rahul your answer is right but we got an exceptional condition.
since the maximum 2 digit number is 99 and after interchanging the digits we get 99 itself.by adding these two we get 198 as sum.So along with 111,220 also be the answer.
220=11*20=11*(11+9).
But according to the logic a and b must be single digit numbers.

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.