Latest TCS Aptitude Question SOLUTION: Which of the following straight lines are perpendicular to each other? 2x+y=8 x=4 y=6 2y=x+3

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Which of the following straight lines are perpendicular to each other?

2x+y=8

x=4

y=6

2y=x+3

Asked In TCS aditi sharma (12 years ago)

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Sushil  (12 years ago)

2x+y=8 is perpendicular to 2y=x+3 and x=4 is perpendicular to y=6;

break equation in y=mx+c type where m is slope of a line and if product of slope of two lines is -1 then they are perpendicular to each other

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biswa  (12 years ago)

1st and 4th line are perpendicular to each other in y = mx +c with slope -2 and 1/2 respectively .

and 2nd perpendicular to 3rd as they parallel to y axis and x axis respectively

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Sushil  (12 years ago)

1st with 4th and 2nd with 3rd

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satish kumar  (12 years ago)

2x + y = 8........(i) and 2y = x+ 3.....(ii) straight lines are perpendicular to each other.
from equation (i), y = -2x + 8 , slope m1 = -2
and from eqn (ii) y = x/2 +3/2 , slope m2 = 1/2
fro perpendicular m1*m2 = -1
here we are getting -2*1/2 = -1
So, (i) and (iv) lines are perpendicular to each other

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dheeraj shukla  (12 years ago)

x=4 is a line parallel to y axis and y=6 is a line parallel to x axis so they both are perpendicular to each other..

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mukesh duboliya  (12 years ago)

first and fourth

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Krishanu Das  (12 years ago)

x=4 is a st line parallel to the y axis and y=6 is parallel to the x axis.So they are perpendicular to each other.

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@SI-IW@NI 12U13EY  (12 years ago)

since x=4 is || to y-axis and y=6 is || to x-axis so they are perpendicular to eachother........now we know that y=mx+c
so from 1st&4th equation's :
y=-2x+8;
y=1/2 + 1.5
comparing both equation's with y=mx+c, we get:
m1=-2 and m2=1/2
for two lines to be perpendicular::product of their slopes=-1
here, m1*m2=-1
so 1st and 4th lines are perpendicular to each other

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