Latest TCS Aptitude Question SOLUTION: a nuber when divided by D give remainder 23 abd when by 12D give 104... what will be remainder when divide by 6D.

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a nuber when divided by D give remainder 23 abd when by 12D give 104... what will be remainder when divide by 6D.

Asked In TCS utkarsh bisht (10 years ago)

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GAURAV JAISWAL  (10 years ago)

for 12d, N can be written as 12dx+104

for d, N = dy + 23

now N will be the same in both cases.

so, N/d = (12dx+104)/d = (dy+23)/d

or, 12x + 104/d = y + 23/d

or, 12x + 81/d + 23/d = y + 23/d

now LHS has to be equal to RHS...

thr4, d should be a factor of 81

since remainder is 23, d>23 which leaves us with d= 27 or 81

take either d = 81 or d = 27, N can be min 12*81 + 104 or 12*27 + 104................................( x = 1)

or, N = 1076 or N = 428

when we divide n by 81 or 27, we do get rem 23 .

now when we divide N by 6*81 = 486 or 6*27 = 162.....we get remainder 104

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JSC  (10 years ago)

let n is the number when it is divided by d.... n= dy +23
" " 12d....n= 12dx +104
6d is a multiple of 12d ..... =2*6dx +104..
so, 6d is also having the same remainder....

Is this solution Helpfull? Yes (3) | No (2)  

NavyaNuchu  (10 years ago)

number be x As dividend=divisor*quot+remainder
x=Dy+23abd
x=12Dz+104
x/6=(12Dz+104)6 thus 104/6=2 as 12 is divisible by 6 any num of form 12*Dz is also divisible by 6 thus will not lead to a remainder.

Is this solution Helpfull? Yes (1) | No (6)  

basanagouda  (10 years ago)

104 only.... on such problems take ur own an easy example and test u ll get the result

Is this solution Helpfull? Yes | No (8)  

Triloki Shaw  (10 years ago)

Number(N)= D*Q+R
N=D*Q+23 and N=12mD+104
ans=104

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