Latest TCS Aptitude Question SOLUTION: form 8 digit numbers from 1,2,3,4,5 with repetition is allowed divisible by 4..

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form 8 digit numbers from 1,2,3,4,5 with repetition is allowed divisible by 4..

Asked In TCS Ramya (10 years ago)

Solved aditya Read Solution (10)

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Read Solution (10) :

aditya  (10 years ago)

no. is divisible by 4 if the no. formed by last two digits is divisible by 4.
so last 2 digits must be
12
32
52
24
44
remaining 1st six digits can be arranged in 5^6 ways.
therefore answer is 5^6+5^6+5^6+5^6+5^6 = 78125

Is this solution Helpfull? Yes (37) | No (5)  

Kundan Kumar  (10 years ago)

when repetition is allowed.
the number is divisible by 4 when its last two digit is divisible by 4
i.e. last two digits can be 12,24,32,44,52
NOW
if last two digit is 12 then 5^6 numbers are possible.
hence for 24,32,44,52
(five ways total)
answer is 5^7 78125

Is this solution Helpfull? Yes (15) | No (4)  

Sachin Grover  (10 years ago)

no. is divisible by 4 if the no. formed by last two digits is divisible by 4.
so last 2 digits must be
12
32
52
24
44
now there are 8 places _ _ _ _ _ _ _ _
Last two digit can be filled in 5 ways
Since repetition is allowed 1st place can be filled in 5 ways, second place can also be filled in 5 ways....same for other 4 places.....so 5^6*5=78125 is the answer.
remaining 1st six digits can be arranged in

Is this solution Helpfull? Yes (4) | No (1)  

Surabhi  (10 years ago)

is it 5^7?

Is this solution Helpfull? Yes (3) | No (4)  

Guru Pranav  (10 years ago)

5^6*5=78125.

Is this solution Helpfull? Yes (3) | No (1)  

sanjay chaubey  (10 years ago)

no. is divisible by 4 if the no. formed by last two digits is divisible by 4.
so last 2 digits must be
12
32
52
24
44
remaining 1st six digits can be arranged in 5^6 ways.
therefore answer is 5^6+5^6+5^6+5^6+5^6 = 78125

Is this solution Helpfull? Yes (2) | No   

jitendra singh  (10 years ago)

62500 ????

Is this solution Helpfull? Yes | No (7)  

vineet chaurasia  (10 years ago)

the answer shuld me 62500.

Is this solution Helpfull? Yes | No (6)  

rohit  (10 years ago)

there will be too many nos , i guess question should be no. of 8 digit nos
just place last two digits so that sum of them is divisible by 4 and calculate no. of combinations

Is this solution Helpfull? Yes | No (2)  

shubhankar barman  (10 years ago)

no. is divisible by 4 if the no. formed by last two digits is divisible by 4.
so last 2 digits must be
12
32
52
24
44
remaining 1st six digits can be arranged in 5^6 ways.
therefore answer is 5^6+5^6+5^6+5^6+5^6 = 78125

Is this solution Helpfull? Yes | No   

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