Latest TCS Aptitude Question SOLUTION: what is the remainder 121212......(300 digit) is divided by 99?

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(#M40026391) TCS Numerical Ability question Keep an EYE

what is the remainder 121212......(300 digit) is divided by 99?

Asked In TCS Manish Tiwari (10 years ago)

Solved MANISH MISHRA Read Solution (15)

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Read Solution (15) :

MANISH MISHRA  (10 years ago)

12%99=12
1212%99=24
121212%99=36
so using this series we get:
1212...300 times%99=12*300/2=1800
1800%99=18
18ANS

Is this solution Helpfull? Yes (39) | No (9)  

prafull mittal  (10 years ago)

12%99=12
1212%99=24(12*2)
121212%99=36(12*3)
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12....300 times%99=12*150
therefore (12*150)%99=18
Ans:- 18

Is this solution Helpfull? Yes (14) | No (5)  

Deepak khera  (10 years ago)

when 12 is divided dy 99,remainder is 12 so pairs of 12 are 150 in 121212......(300 digit)so calculate 150%99 = 1.5, 12 multiplied with 1.5 gives 18.

Is this solution Helpfull? Yes (13) | No (9)  

Manish Tiwari  (10 years ago)

The correct answer is 18.

Is this solution Helpfull? Yes (7) | No (5)  

rishabh raj  (10 years ago)

we have to check for 9*11
the given number is divisbl by 9 as the sum is divisible by 9.
for 11 it the difference of the (sum of the even place - the sum of odd place) shud be equal to 0 or divisible by 11. but it gives a remainder 7 so the remainder will be 7

Is this solution Helpfull? Yes (5) | No (3)  

Piyush TAk  (10 years ago)

12%99*150%99=====>18

Is this solution Helpfull? Yes (4) | No (2)  

kuldeep kumar  (10 years ago)

(12*150)/99 so the correct ans is 36

Is this solution Helpfull? Yes (4) | No (5)  

seetha  (10 years ago)

121/99===> remainder = 22 now 12121212121....300 = (121)(121)...100
so, (22*100)/99 ====> rem 22

Is this solution Helpfull? Yes (3) | No (10)  

ganesh chemanchula  (10 years ago)

I think question is about remainder..not quotient
so ans will be 2..

Is this solution Helpfull? Yes (3) | No   

Tanya Saxena  (10 years ago)

12(10^0+10^2+............+10^298)
12((10^2)^0+(10^2)^1+.........+(10^2)^149)
100%99=1
SO, 12(1+1+1+..........+149 TIMES)
12*149mod99
4*149 mod 33
4*17 mod 33
68mod33
=2
ans

Is this solution Helpfull? Yes (2) | No (2)  

rishabh raj  (10 years ago)

sorry there was a mistake in my solution
we have to check for 9*11
the given number is divisbl by 9 as the sum is divisible by 9.
for 11 it the difference of the (sum of the even place - the sum of odd place) shud be equal to 0 or divisible by 11. but it gives a remainder 7
so 18 will be its answer as 18 is completely divided by 9 and it gives 7 as remainder as well when divided by 11..

Is this solution Helpfull? Yes (2) | No (2)  

Guru Pranav  (10 years ago)

1212%99 =24,
12121212%99=48=24*2
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1212....300= 75*24%99=18 Ans.

Is this solution Helpfull? Yes (1) | No (1)  

kk  (10 years ago)

121%99=22
121121%99=22*2
as we taken three terms bcoz given 300(3 digit)
so taken 121 then 121121....
upto 121121.....upto 300term=(22*100)%99=22 so ans is 22

Is this solution Helpfull? Yes (1) | No (2)  

seetha  (10 years ago)

soory we need to consider 121212 /99 it leaves a remainder 36
so 36*50/99 leaves a remainder 18

Is this solution Helpfull? Yes | No (4)  

PRADAP  (10 years ago)

18 is the ans

Is this solution Helpfull? Yes | No (4)  

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