Latest Elitmus Aptitude Question SOLUTION: if (1/a)+(1/b)+(1/c)= (1/a+b+c), (a*b*c)& (a+b+c) dos not equal to zero. And if x = (a+b)*(b+c)*(c+a)+(a+b+c) then which is true about x?? 1-> x x>0 3->both 1 and 2nd

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(#M40026409) ELITMUS question APTI Keep an EYE

if (1/a)+(1/b)+(1/c)= (1/a+b+c), (a*b*c)& (a+b+c) dos not equal to zero. And if x = (a+b)*(b+c)*(c+a)+(a+b+c) then which is true about x??

1-> x x>0 3->both 1 and 2nd

Asked In Elitmus neeraj (10 years ago)

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Adarsh Panicker  (10 years ago)

It's option b. x>0;

(1/a)+(1/b)+(1/c)=1/(a+b+c) --> Given

Solving this equation we get.

a*a*b + a*a*c + a*b*b + c*b*b + a*c*c + b*c*c + 2(a+b+c) = 0 ......(equation 1)

x = (a+b)*(b+c)*(c+a)+(a+b+c) (Given)

Solving this we get...

x = a*a*b + a*a*c + a*b*b + c*b*b + a*c*c + b*c*c + 2(a+b+c) + (a+b+c)

By equation (1)

x = 0 + (a+b+c) and we knoe (a+b+c)!= 0
so looking at the option option b is correct i.e. x>0

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neeraj  (10 years ago)

option 1 is x0. actually that was a typing mistake

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