Latest TCS Aptitude Question SOLUTION: 1,6,7,13,20 33 so on......find the sum of first 52 terms

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(#M40028731) TCS question Keep an EYE

1,6,7,13,20 33 so on......find the sum of first 52 terms

Asked In TCS vishal kumar singh (10 years ago)

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Debolina Chakraborty  (10 years ago)

as 1+6+7 is sum upto 3rd tem n it is 5th term -6, similarly
as 1+6+7+13+20+33+53 is sum upto 7th term and is equal to 9th term 139-6=133
hence sum upto 52nd term is 54th term-6
using golden ratio we can solve this, bt to be more accurate we calculate a few more terms. 1,6,7,13,20,33,53,86,139,225,364,589,953,1542....
thus 54th term= 1542*(1.6180339)^40
hence sum upto 52nd term is 352849113676-6=352849113670

Is this solution Helpfull? Yes (6) | No (1)  

abhishek rastogi  (10 years ago)

by mistake i have given the solution here for the below question ,plz excuse

Is this solution Helpfull? Yes (2) | No (6)  

SUMAN KUMAR  (10 years ago)

# include
# include
int main()
{
long int a = -4, b = 5, c = 0, i, n, sum = 0 ;

printf("Enter the limit : ") ;
scanf("%d", &n) ;
printf("nThe fibonacci series is : nn") ;
for(i = 1 ; i

Is this solution Helpfull? Yes (1) | No (26)  

SUMAN KUMAR  (10 years ago)

long int a = -4, b = 5, c = 0, i, n, sum = 0 ;
printf("Enter the limit : ") ;
scanf("%d", &n) ;
printf("nThe fibonacci series is : nn") ;
for(i = 1 ; i

Is this solution Helpfull? Yes (1) | No (22)  

divyasha  (10 years ago)

352849027131.

Is this solution Helpfull? Yes (1) | No   

dipu  (10 years ago)

ths is not c program compitition @suman

Is this solution Helpfull? Yes (1) | No   

SUMAN KUMAR  (10 years ago)

MATHEMATICALLY PROCESS IS TOO LENGTHY
SO........EASIEST WAY.......after running the program enter value of n=52
# include
# include
int main()
{
long int a = -4, b = 5, c = 0, i, n, sum = 0 ;

printf("Enter the limit : ") ;
scanf("%d", &n) ;
printf("nThe fibonacci series is : nn") ;
for(i = 1 ; i

Is this solution Helpfull? Yes | No (41)  

SUMAN KUMAR  (10 years ago)

for(i=1;i

Is this solution Helpfull? Yes | No (20)  

abhishek rastogi  (10 years ago)

2(10C3*3!*7!+ 10C4*4!*6!+ 10C5*5!*5!+10C6*6!*4!+ 10C7*7!*3!+10C8*8!*2!+ 10C9*9!*1!+ 10C10*10!)

Is this solution Helpfull? Yes | No (11)  

raja babu  (10 years ago)

as of previous formula here also is S(n)= S(n+2)-S(2)
but 54th term is unknown..

Is this solution Helpfull? Yes | No (4)  

Vishakha  (10 years ago)

Sn=n(a1+an)/2
Here,a1=1 and an=(1+(52-1)d) where, d=(6-1)
hence,an=307
Sn=52(1+307)/2
so...8008 (ans)

Is this solution Helpfull? Yes | No (15)  

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