Latest Capgemini Aptitude Question SOLUTION: Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?

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Train A starts from Meerut at 12:00 pm & reach at Delhi on 2:30 pm & train B starts from Delhi at 12:15pm and reach at Meerut on 2:15pm. So, when both trains crosses each other ?

Asked In Capgemini Sagar kumar (10 years ago)

Solved chaitanya Read Solution (9)

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Read Solution (9) :

chaitanya  (10 years ago)

Let the distance between Meerut & Delhi be x kms
&
let trains meet y hours after 12.15pm

Speed of A= x/150 kms/min.
speed of B = x/120 kms/min.

Distance covered by A in (y+15) min+distance covered by B in y hours
=x (x/150)* (y+15) + (x/120) * y = x
Equating the equations Y=60
Hence trains meet at 1.15 pm.

Is this solution Helpfull? Yes (23) | No (6)  

rakesh kumar  (10 years ago)

take the distance to be 1 km between Delhi and Meerut.
so speed of A 1/2.5 and speed of B 1/2.
relative speed =1/2.5+1/2=9/10.
after 15 min position of A
(1/2.5)*(15/60)=1/10 from meerut.
so distance between A and B at 12.15=9/10.
relative speed=9/10.
so the trains meet after 1 hr at 1:15 p.m

Is this solution Helpfull? Yes (6) | No (2)  

suman kumar  (9 years ago)

since train A reach in 2.5 hr and B in 2 hr.
so B's speed (5/4) times of A.
at 1:15 both will be at middle since B started at 12:15 and A at12:00.
ans(1:15 pm)

Is this solution Helpfull? Yes (5) | No   

ASHISH KUMAR MISHRA  (10 years ago)

Ans is :1:05pm ;
Train Place1_with time ) Place2_(with time ) Time_taken
A: meerut(12:30pm) delhi(2:30pm) 5/2hr
B: Delhi(12:15pm) meerut(2:15pm) 2hr
Now,
let distance b/w station is D km
Va=2D/5 kmph;
Vb=D/2 kmph;
Now train B started after 15 mint so meanwhile train A traveled D/4 km distance;
So relative distance between trains is = D-D/4=>3D4;
Now time of crossing = Relative distance /relative velocity= (3D/4)/(2D/5+D/2)=5/6 hr =>50 min
Now taking B train in Consideration time of crossing is = 12:15pm+(50min)=1:05pm ;

Is this solution Helpfull? Yes (4) | No (6)  

chinmoy sau  (10 years ago)

(there r two many unknown variables so we need some assumptions...)let distance be 1km between two
so s1=speed of 1st train=2/5
s2=speed of 2nd =1/2
let they meet in x hrs then d1=s1*x
d2=s2*(x-15/60)
d1+d2=1

Is this solution Helpfull? Yes (2) | No (1)  

vijay kholiya  (5 years ago)

Ratio of time by train A and B ->150:120
15:12
5:4
Difference between two is 1 part and that 1 part = 15 min(Train B started 15 mins later)
So 15min*5=75 min after Train A starts is answer i.e 1:15pm
or 15min*4=60min after Train B starts is answer i.e 1:15pm.

Is this solution Helpfull? Yes (2) | No   

surendra sr  (10 years ago)

both the train travel between fixed distance . so let distance = x
time taken by t1=2.5h and t2=2h
so x=v1*2.5 and x=v2*2. and v1v2=22.5
when both the train will meet at that clock watch read same time let t a clock.
therefore v1*(2.5-t)=v2*t....
solving this get t=1.11h=66.666 minute therefore 12:15+1.06=13.21 pm = 1.21 pm

Is this solution Helpfull? Yes (1) | No (4)  

vijay kholiya  (5 years ago)

Ratio of time by train A and B ->150:120

Is this solution Helpfull? Yes | No (2)  

vijay kholiya  (5 years ago)

Ratio of time by train A and B ->150:120

Is this solution Helpfull? Yes | No (2)  

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