Latest TCS Aptitude Question SOLUTION: 27. Find the minimum value of abs (187m -396n + 526) where m and n are integers, if x > 0 abs(x) =x and if x < 0 then abs(x) = -x

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40028870) TCS question Keep an EYE

27. Find the minimum value of abs (187m -396n + 526) where m and n are integers, if x > 0 abs(x) =x and if x < 0 then abs(x) = -x

Asked In TCS TCS 2014 (10 years ago)

Unsolved Read Solution (8)

Is this Puzzle helpful?   (2)   (3) Submit Your Solution

Read Solution (8) :

RAKESH  (10 years ago)

let x=187m-396n+526
for x to be minm (187m-396n) must be nearer to -526
x=11(17m-36n)+526
for m=12 & n=7,the value of x=-2
so minm value of abs(x)=2
is it right?

Is this solution Helpfull? Yes (8) | No (5)  

vineesha  (10 years ago)

cannot be determined.....
as we have to find the min value 187m-396n+526 should be negative
as m and n are integers we can take m as least neg int and n as max int...

Is this solution Helpfull? Yes (7) | No (7)  

RAKESH  (10 years ago)

as per defn of abs(x)
the value of abs(187m-396n+526) will be always positive or maybe zero but cant -ve
for minm value of given expression the term (187m-396n+526) mustbe least +ve or zero or max -ve
for m=12 & n=7,the value of x=-2
as |-2|=-(-2)=+2
so minm value of abs(x)=2

Is this solution Helpfull? Yes (6) | No   

Pradeep   (10 years ago)

Sorry for the last answer and
the answer is 2 by simply substituting the given m n values from options
11*ABS(17m-36n)=-526
Here m=12. n=7
Ans 2

Is this solution Helpfull? Yes (3) | No   

Naba Paul  (10 years ago)

@vineesha a small rectification here...see abs(x)=-x.Therefore, here has to be maximum for abs(x) to be minimum. hence, n=0,m=(+)infinite. ans; cannot be determined.

Is this solution Helpfull? Yes | No (1)  

Pradeep   (10 years ago)

When m=1. n=2. then
ABS(x)=79

Is this solution Helpfull? Yes | No (3)  

vineesha  (10 years ago)

@naba paul
if we take n=0 and m as max +ve integer then value in abs is positive value....
abs(+value)=+value.....that means we get max value of abs(187m-396n+526)...
but here we want min value of abs(......).
if we take m as max -ve value and n as max +ve value then 187(-ve)-396(+ve)+526
that means -()-()+526 then we get abs(-ve)...as abs(-ve) is -ve we get min value of abs(.......).
am i correct?

Is this solution Helpfull? Yes | No   

Chirag Ranjan Lahiri  (9 years ago)

the value of abs(187m-396n+526) will be always positive or maybe zero but cant -ve
for minm value of given expression the term (187m-396n+526) mustbe least +ve or zero or max -ve
for m=12 & n=7,the value of x=-2
as |-2|=-(-2)=+2
so minm value of abs(x)=2

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.