Latest TCS Aptitude Question SOLUTION: There are 2 triangles in a circle ( triangles are in the shape of the star) What is the area of the circle not covered by traingles?

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There are 2 triangles in a circle ( triangles are in the shape of the star) What is the area of the circle not covered by traingles?

Asked In TCS Ankit Bansal (10 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

Rohit Singh  (10 years ago)

one thing is missing length of equilateral triangle..in original questn it is 12..
given that two equilateral triangles of length 12 has inscribed in a circle.

Altitude of the triangle = (sqrt3/2)*a = √3/2(12) = 6√3
We know that centroid divides the altitude in the ratio 2 : 1 and 2:3(Altitude) = Circum radius
Circum radius = 2/3(6sqrt3)=4sqrt3
Area of the circle = πr2=3.14×(4√3)^2
Now the two triangles in the circle forms 12 small equilateral triangles with side 4. So their total area = 12×(√3/4)*a^2 = (12×√3/4)*4^2
Area which is not covered by the equilateral triangles = 3.14×(4√3)^2 - )12×√3/4)*4^2 = 67.65 ≃68

Is this solution Helpfull? Yes (7) | No   

sachin  (10 years ago)

data not sufficient

Is this solution Helpfull? Yes (6) | No (1)  

RAKESH  (10 years ago)

there must be a value of side or radius
ans is (pi-1.732)R^2

Is this solution Helpfull? Yes (3) | No (2)  

sourav mukherjee  (10 years ago)

ans is 68...

Is this solution Helpfull? Yes (1) | No (9)  

RGN  (10 years ago)

Ans: area of the circle-2*area of the each triangle

where possible triangle is only isosceles triangle.

Is this solution Helpfull? Yes (1) | No (3)  

DEEPANSHI SRIVASTAVA  (10 years ago)

PI*r^2-b*h

Is this solution Helpfull? Yes | No (4)  

Sayan Banerjee  (10 years ago)

Can you plz explain the solution Sourav.

Is this solution Helpfull? Yes | No (4)  

Palash Monga  (10 years ago)

there is no way we can find the ans

Is this solution Helpfull? Yes | No   

ronak roy  (10 years ago)

since two triangle form 4 isosceles triangle
if diameter of circle is 2a
then area of each isosceles traingle is root(2)a/4(roo(4a^2-(root(2)a)62)
=a/2
then area of 4 triangle is 4*a/2=2a
area of circle is pi*a*a
then result is pi*a^2-2a
is it right???

Is this solution Helpfull? Yes | No (4)  

Subhajit Halder  (10 years ago)

ans is = [area of circle - {2*area of triangle_1 - (2*area of triangle_2+ area of square)}]

Is this solution Helpfull? Yes | No (1)  

madhurima gorai  (10 years ago)

if the triangles are equilateral triangles then the area not covered by the triangles = area of the circle-(2*area of triangle)-area of the hexagonal part covered in the triangle twice.
let the sides of the triangle be "a" then the sides of the hexagon will be "a/3"
area of the hexagon=(3root3(a/3)^2)/2

Is this solution Helpfull? Yes | No   

Chirag Ranjan Lahiri  (9 years ago)

there must be a value of side or radius
ans is (pi-1.732)R^2

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