Latest self Aptitude Question SOLUTION: This is a simple Number System Problem, posted under Placement Category Let x, y and z be distinct integers. x and y are odd and positive, and z is even and positive. Which one of

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(#M40002962) SELF question Number Keep an EYE

This is a simple Number System Problem, posted under Placement Category

Let x, y and z be distinct integers. x and y are odd and positive, and z is even and positive. Which one of the following statements cannot be true?

1)(x-z)2 y is even 2)(x-z)y2 is odd 3) (x-z)y is odd 4)(x-y)2z is even

Solution

i think, in this question in options, 2 used is not multiplied number, it is square
so by checking first is (odd-even)^2 * odd = odd
but it is given even so it will be incorrect

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Ankit (12 years ago)

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