Latest TCS Aptitude Question SOLUTION: what will be last two digit of 4761^235

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what will be last two digit of 4761^235

Asked In TCS ATIQUR RAHMAN (10 years ago)

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RAKESH  (10 years ago)

unit place of 4761^235=1
10th place of 4761^235=(10th place of 4761)*(unit place of 235)=6*5=0
so,last two digit of 4761^235=01

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ashish  (10 years ago)

any number ending with with 1
for example (XX61)^n , n---->be anything
unit digit will always be 1
and for the tens digit :multiply tens digit(of the number) with unit digit of power
i.e. tens digit of number--> 6
and unit digit of power --> 5
so 6*5=30
i.e. nothing but 0 @tens place
so answer =01

Is this solution Helpfull? Yes (14) | No (1)  

hitesh kumar gupta  (10 years ago)

http://totalgadha.com/mod/forum/discuss.php?d=4405
very helpful soln

Is this solution Helpfull? Yes (4) | No   

chandan kumar  (10 years ago)

last two digit will be 01

Is this solution Helpfull? Yes (1) | No (1)  

alok kumar  (10 years ago)

ans should b 21

Is this solution Helpfull? Yes (1) | No (7)  

satyam shivam  (10 years ago)

ans is 01

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Abhishek Kumar  (10 years ago)

01 is the right answer

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ranjit mangaraj  (10 years ago)

4761^235 last 2 digit depend on 61
















6

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Arindam Dhara  (10 years ago)

check the cyclicity of 61 its 5 and the 5th iteration is 01
ans is 01

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abhi  (10 years ago)

lasrt digit will be 1 as unit digit is 1
tens digit i will be 0 as (tens digit of base * multiply with unit digit of expo)=5*6=30 so 0 is take
hence 01 is answer

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Raju  (10 years ago)

4761's unit digit=1 and 1^5=1
and 10th digit of 4761 is 6 and 6^5=30
so last two digit will be 01

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NAROTAM JANGIR  (10 years ago)

first place of 4761^235 from right to left is 1
second place of 4761^235 from right to left is=(second place of 4761 from right to left is)*(unit place of 235 from right to left is)=6*5=0
last two digit of 4761^235=01

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satarupa chakrabarty  (10 years ago)

ans is 01 as taking last two digits from 4761.((61)^5)^47) as 235=47 * 5 .61^5=01 now (01)^47=01.

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Dhanashree Shirke  (10 years ago)

235/4 remainder=3 so 4761^3= last two digit =31

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Anjani Anand  (10 years ago)

ans 35, (4760+1)235=118600+235

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soham ghosh  (10 years ago)

ANS=61
please find the cycle of 61.you will get it is 6.
235/6 leaves the reminder 1.so last two digit will be equivalent to 61^1
that is 61

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Guru Pranav  (10 years ago)

01

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