Latest TCS Aptitude Question SOLUTION: How many digits formed using 1,2,3,4 & 5. (If repitation is possible)

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How many digits formed using 1,2,3,4 & 5. (If repitation is possible)

Asked In TCS surendra raju (10 years ago)

Solved madhusudhan rao Read Solution (15)

Is this Puzzle helpful?   (16)   (3) Submit Your Solution Permutation and Combination

Read Solution (15) :

madhusudhan rao  (10 years ago)

one digit-5
two digit-5^2
3 digit-5^3
4digit-5^4
5 digit-5^5..the total is addition of all those numbers

Is this solution Helpfull? Yes (37) | No (2)  

Mahesh Patil  (10 years ago)

5(SINGLE DIGIT)+25(TWO DIGIT)+125(THREE DIGIT)+625(FOUR DIGIT)+3125(FIVE DIGIT)=4025(ANSWER)

Is this solution Helpfull? Yes (10) | No (5)  

Venkata Siva Gandikota  (10 years ago)

5^5
when repetition allowed =n^r

Is this solution Helpfull? Yes (6) | No (2)  

Prayosha panchal  (10 years ago)

5^5 digits=3125 can be formed

Is this solution Helpfull? Yes (3) | No (1)  

Pradeepa.R  (10 years ago)

As per the given question,first digit=5ways,second digit=5ways......fifth digit=5ways
so the answer is 5C1*5C1*5C1*5C1*5C1=5*5*5*5*5=5^5=3125.

Is this solution Helpfull? Yes (3) | No   

Kaustubh Karekar  (10 years ago)

3245

repetition is possible means each number can come 5 times + all numbers together

Is this solution Helpfull? Yes (2) | No   

rahul jha  (10 years ago)

each place can be filled in 5 ways thus its 5*5*5*5*5=5^5

Is this solution Helpfull? Yes (2) | No (1)  

aravind  (10 years ago)

when repition is possible then no.of digits formed is 5^5

for suppose here they ask how many 4 digits can formed the the ans is 5 ^4.....

Is this solution Helpfull? Yes (1) | No   

Nikunj  (10 years ago)

Don't Know

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Sajib Ghosh  (10 years ago)

5^5
bcoz in every position of the digit we can use that number again..
suppose a 5 digit number *****,,in 1st position I can use any number from 1,2,3,4,5,,so no. of choices is 5 to make a one digit no. ..similarly in 2nd position I can also use any number from 1,2,3,4,5 since repetition is allowed.. so to make a two digit total no of choices 5*5 .. to make five digit 5^5..uff!! i think this solution is helpful.. :)

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Shashank gupta  (10 years ago)

5^5 digits can be formed

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kantrhideep  (10 years ago)

Ans: 5 digits are formed
Exp: in the question asked for digits not for numbers ....
Digit means containing only one digit

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pullisrinivasareddy  (10 years ago)

without repetition means simply n^n.

Is this solution Helpfull? Yes (1) | No   

hemant panchal  (10 years ago)

n P r = n!/(n-r)! = 5 P 5 = 5!/0! =120
5 P 4 = 5!/1! = 120
5 P 3 = 5!/2! = 60
5 P 2 = 5!/3! = 20
5 P 1 = 5!/4! = 5
hence,
no. of digits formed = 5 P 5 + 5 P 4 + 5 P 3 + 5 P 2 + 5 P 1
= 120 + 120 + 60 + 20 + 5
= 325

Is this solution Helpfull? Yes (1) | No (2)  

bharath kopparapu  (10 years ago)

is solution for number of digits or number of numbers.

Is this solution Helpfull? Yes | No (2)  

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