Latest Elitmus Aptitude Question SOLUTION: Q. ABCD is a square. P is the mid point of AB. the line passing through A and perpendicular to DP intersects the diagonal at Q and BC at R, If AB =2 then PR=?

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Area and Volume

Elitmus Question Papers:

(#M40031126) ELITMUS Numerical Ability question Keep an EYE

Q. ABCD is a square. P is the mid point of AB. the line passing through A and perpendicular to DP intersects the diagonal at Q and BC at R, If AB =2 then PR=?

Asked In Elitmus niharika kumari (10 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (13)   (10) Submit Your Solution Area and Volume

Read Solution (5) :

amrita kumari  (10 years ago)

Let the line passing thru A meet DP in E.

So In triangle DAP

DP= Sqroot(5)

AE=2/Sqroot(5)

triangle AEP is similar to triangle ABR

So AR= sqroot(5)

=>RB=1

=> PR=Sqroot(2)

Is this solution Helpfull? Yes (11) | No (17)  

vishal singh thapa  (10 years ago)

let E is point of intersection of line AR.
IN TRIANGLE ADP;
WE GET,
OP=SQRT(5).
now in similar triangles AEP AND ADP (By angle p in both triangles is common and one side AP is also common)
therefore
AP/DP=EP/AP
AP^2= EP*DP
1=EP*SQRT(5)
SO, EP=1/SQRT(5)
AGAIN IN SIMILAR TRIANGLES APE AND PER(BY ONE SIDE EP IS COMMON)
AP/PE=PE/PR
AP*PR=PE^2
1*PR={1/SQRT(5)}^2
HENCE, PR=1/5.
WHICH IS REQUIRED VALUE OF PR.

Is this solution Helpfull? Yes (4) | No (4)  

Rathinamoorthy N  (10 years ago)

Ans : square root of 2. if u draw the diagram it will give u an triangle where u can apply pythagoras theorem..

Is this solution Helpfull? Yes (1) | No (2)  

kumar madhav  (10 years ago)

Plesse give options

Is this solution Helpfull? Yes | No (3)  

ashish  (6 years ago)

underroot(29) / 5.

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.