Latest TCS Aptitude Question SOLUTION: 8+88+888+8888...upto 24 terms. what are the last three digits?

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8+88+888+8888...upto 24 terms.
what are the last three digits?

Asked In TCS haran (10 years ago)

Solved RAKESH Read Solution (4)

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RAKESH  (10 years ago)

8+88+888+8888...upto 24 terms

simply add

unit digit=(8+8+8+... 24 times)= 24*8=192,
unit digit=2, carry=19

tenth digit=(8+8+...23 times)+19=184+19=203,
tenth digit=3, carry=20

hundredth digit=(8+8+...22 times)+20=176+20=196,
hundredth digit=6 & so on

last three digits= 632

Is this solution Helpfull? Yes (133) | No (3)  

amanul khan  (10 years ago)

simply multiply...
8*24=192(2 unit digit and 19 carry)
8*23=203(3 unit digit and 20 carry)
8*22=196(6 unit digit and 19 carry)
ans=632.

Is this solution Helpfull? Yes (6) | No   

dillibai  (10 years ago)

In unit's place there are 24 8's so,24*8=192
in ten's place 23 8's so,23*8=184
in 100's place 22 so,22*8=176
therefore 632 = (176+20=196)6 (184+19=203)3 (192)2

Is this solution Helpfull? Yes (1) | No   

Rajat Jain  (9 years ago)

simply visualise we have to calculate last three digit so digit before last three is of no use now we will be having 8+88+888+888+888+888+888 upto 24term so we are having 2 term who are not having 8 in all three do keep them aside now 22 term will be having 888 so 888*22 last three digit 536 now add 88 and 8 in it so we will get 632

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