Latest CTS Aptitude Question SOLUTION: Q. A motor cycle is moving with the speed of 47.52 km/hr and the radius of the wheel of the motorcycle is 21 cms. Calculate the approximate no of revolutions made by the wheel in o

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Q. A motor cycle is moving with the speed of 47.52 km/hr and the radius of the wheel of the motorcycle is 21 cms. Calculate the approximate no of revolutions made by the wheel in one minute.
Option
A) 400 rpm
B) 500 rpm
C) 600 rpm
D) 700 rpm

Asked In CTS Soumya Ranjan Sahoo (10 years ago)

Solved Akanksha Mishra Read Solution (6)

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Read Solution (6) :

Akanksha Mishra  (10 years ago)

Given Speed = 47.52 km/h = 47.52 * 1000/60 m/s
= 792 metre/minute
the radius of the wheel of the motorcycle = 21 cm
circumference of the wheels = 2*22/7*21 = 132cm = 1.32 m

Number of revolutions made by the wheel in one minute
= Speed (in metre/minute)/circumference(in m)
= 792/1.32 = 600
So no of revolutions made by the wheel in one minute will be 600

Is this solution Helpfull? Yes (38) | No   

ayush jha  (10 years ago)

1 rev=2*(22/7)*21 cm=132 cm
speed=47.52 km/hr=79200 cm/sec
therefore no of revolution in in 1 min=79200/132=600 ans
ans: c

Is this solution Helpfull? Yes (5) | No   

Satyam Pradhan  (9 years ago)

Distance covered in 1 hr(60 min)=47.52km
So, distance covered in 1 min= (47.52/60) =0.792km=0.792*1000*100=79200cm

Now ,Distance coverd in 1 revolution of wheel=2*pi*r=2*(22/7)*21=132 cm

So total no of revolution to cover 79200 cm= 79200/132=600 rpm

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shalu singh  (10 years ago)

ans:600rpm

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punnam raju  (10 years ago)

shalu singh don't give the answer directly, readers are not as clever as u

Is this solution Helpfull? Yes (1) | No   

manideep Latchupatula  (8 years ago)

Anyone explain me in a simple method pls !!!

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