Latest CTS Aptitude Question SOLUTION: A peacock of flying speed 5 km/h is sitiing on a top of a wooden pole of height 10m. There is a hole in the pole downwards and a snake is approaching that hole which is 21m away fr

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(#M40033031) CTS Numerical Ability question Time & Distance Keep an EYE

A peacock of flying speed 5 km/h is sitiing on a top of a wooden pole of height 10m. There is a hole in the pole downwards and a snake is approaching that hole which is 21m away from the snake.How much time it will take for the peacock to catch the snake before it enters the hole.

Asked In CTS (10 years ago)

Solved Snehasis Read Solution (6)

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Read Solution (6) :

Snehasis  (10 years ago)

Speed of the peacock = 5 km/h(given)
Distance of the pole = 10m(given)
Distance between the pole hole and snake = 21m(given)

Therefore, we have to first find the distance between the peacock and the snake.

This can be done by using Pythagora's Theorem,

Therefore, 21^2 + 10^2 = 23.26 metre(approx)

Speed of the peacock = 5 km/h or 1.39 metre/sec(approx)

Now, we know can find the time for peacock to catch the snake by,

Time = Distance/Speed

= 23.26/1.39

= 16.73 seconds(approx)

Therefore, the required time for peacock to catch the snake before it enters the hole of the pole is 16.73 seconds.

Is this solution Helpfull? Yes (63) | No (6)  

Electron  (10 years ago)

Here snake is approaching the hole. that means we need to know the speed of the snake also to find the time required to catch the snake.

Is this solution Helpfull? Yes (6) | No (8)  

Princy  (10 years ago)

peacock(5km/hr)
|
10m |
|
|____________snake
21m

now ,distance betwn peacock and snake(considered as x) can be foundd with pythagoras theorem.
x^2 =10^2+21^2
=100+441
=541
therefore x=23.26 meters(approx)

now, we have distance = 23.26 meters
speed = 5 km/hr = 1.39 m/s (i.e 5*5/18 m/sec)

time=distance/speed
=23.26/1.39
= 16.73 sec
Ans= 16.73 seconds

Is this solution Helpfull? Yes (5) | No (3)  

revathi.s  (10 years ago)

pls explain in clear

Is this solution Helpfull? Yes (2) | No (9)  

varun indra  (10 years ago)

The answer is 16.73 s as solved by snehasis but actually the question mentions that the snake is approaching the hole which means its moving and thus has a speed.Now dost=23.26m by P.T
time=Dist/Relative speed of peacock wrt snake but here speed of snake is not given so it is not taken into account

Is this solution Helpfull? Yes (2) | No (1)  

suman kumar  (9 years ago)

peacock flying speed 5 km/h so in(m/s) is (25/18)m/s;
wooden pole of height 10m;
21m away from the snake;
time it will take for the peacock to catch the snake before it enters the hole=10/(25/18)=7.2seconds

Is this solution Helpfull? Yes (1) | No (3)  

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