Latest TCS Aptitude Question SOLUTION: In how many possible ways can write 3240 as product of 3 positive integers a,b,c

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(#M40033218) TCS Numerical Ability question permutations and combinations Keep an EYE

In how many possible ways can write 3240 as product of 3 positive integers a,b,c

Asked In TCS sindhu (10 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

varsha  (9 years ago)

3240=2*2*2*3*3*3*3*5;
=8!/3!*4!;
280

Is this solution Helpfull? Yes (3) | No (3)  

ChandrakanthMamilla  (8 years ago)

3240 = 2*2*2*3*3*3*3*5

we have the formula to arrange 3+ve integers as (n+r-1) C (r - 1)

so arranging 2 as ------> (3+3-1) C (3-1) = 10 ways

3 as ------> (3+4-1) C (3-1) = 15 ways

5 as ------> 3 ways

therefore total no of possible ways of writing 3240 as product of 3+ve integers = 10 * 15 * 3
= 450 ways

Is this solution Helpfull? Yes (3) | No   

vikash kumar  (9 years ago)

the factors of 3240 are 5,2,3,3,3,2
so the no of ways are (6*5*4)/3!2!1!=10
Becoz we are arranging the values in 6*5*4 but some value are repeated so we have to divide these values so the answer will be 10

Is this solution Helpfull? Yes (2) | No (24)  

himanshu mittal  (9 years ago)

there can also be combined no. at each position....
so true answer is still ambiguous

Is this solution Helpfull? Yes | No (5)  

Gagandeep Jaswal  (9 years ago)

60 ways! 3240 has factors- 2,2,2,9,9,5
therefore soln is :- 6!/2!*3!=60 ways

Is this solution Helpfull? Yes | No (4)  

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