Latest Elitmus Aptitude Question SOLUTION: how many six digits numbers can be formed using the digits 1to 6, without repetition. such that the number is divisible by the digits at its unit place

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Number System

Elitmus Question Papers:

(#M40033416) ELITMUS Numerical Ability question permutation Keep an EYE

how many six digits numbers can be formed using the digits 1to 6, without repetition. such that the number is divisible by the digits at its unit place

Asked In Elitmus shashank (10 years ago)

Unsolved Read Solution (7)

Is this Puzzle helpful?   (2)   (6) Submit Your Solution Number System

Read Solution (7) :

Vivek Jain  (10 years ago)

_ _ _ _ _ 1 =>5*4*3*2*1
_ _ _ _ _ 2 =>5*4*3*2*1
_ _ _ _ _ 3 =>5*4*3*2*1
_ _ _ _ _ 4 =>2*4*3*2*1=48 (Tens place can have either 2 or 6)
_ _ _ _ _ 5 =>5*4*3*2*1
_ _ _ _ _ 6 =>5*4*3*2*1
Total: 120*5 + 48 =648 ans

Is this solution Helpfull? Yes (32) | No (6)  

Rohit  (10 years ago)

divisible by 1 --120
2---120
3---120
4----48
5----120
6 ---120
total = 648ans.

Is this solution Helpfull? Yes (8) | No (2)  

sriharsha palvadi  (10 years ago)

unit digit 1:120
2:120
3:120
4:48
5:120
6:120
total=648

Is this solution Helpfull? Yes (3) | No (1)  

Mani kandan  (10 years ago)

2*4*3*2*1=48 (Tens place can have either 2 or 6)

i cannot understand this. why tenth digit used in this.

Is this solution Helpfull? Yes (1) | No   

Neelu  (10 years ago)

plz explain step by step....cant understand

Is this solution Helpfull? Yes | No (1)  

devender  (10 years ago)

numbers ending with 1,2,5 and 6 will respectively be divisible by their unit digit. hence total no. ending with 1,2,5 and 6 are 4*(5!)=480.
and numbers ending with 3 are not all divisible by 3.so consider the series 3,33,63,93------.here we get the clue that no. ending with 3 and divisible by 3 are located at a distance of 30.
now total no. divisible by 3=120 and out of them divisible by 3 are 120/30=4.
similarly no. ending with 4 and divisible by 4 are located at a distance of 20.
now total no. divisible by 4=120 and out of them divisible by 4 are 120/20=6.
hence total numbers divisible by by the digits at unit place are =480+6+4=490.
hence 490 ans.

Is this solution Helpfull? Yes | No (1)  

sourav tripathi  (10 years ago)

-----1=120
-----2=120
-----5=120
-----3=24 (only numbers ending with ----63)
-----6=24 (only numbers ending with ----36)
-----4=48 (only numbers ending with ----24 and ----64)
total = 120+120+120+24+24+48 = 456 ans

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.