Latest TCS Aptitude Question SOLUTION: A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze? (a) 38.5 sq.m (b) 155 sq.m (c) 144 sq.m (d) 19.25 sq.m PLEASE EXPLAIN ALSO

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(#M40003348) TCS Logical Reasoning question Keep an EYE

A goat is tied to one corner of a square plot of side 12m by a rope 7m long. Find the area it can graze?
(a) 38.5 sq.m
(b) 155 sq.m
(c) 144 sq.m
(d) 19.25 sq.m
PLEASE EXPLAIN ALSO..

Solution

38.5 sq m

Area covered by goat = Pi*r^2/4 ( here we divide by 4 because rope is tied at the corner of the plot and only 1/4 part , the goat can graze
where r= 7 m = length of rope

so area = (22/7)*7*7/4 = 38.5 sq m
This answer is given by DIPIN and is correct answer

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Asked In TCS arjun (12 years ago)

Solved Dr.Dipin Singh Read Solution (16)

Is this Puzzle helpful?   (43)   (15) Submit Your Solution General Mental Ability

Read Solution (16) :

Dr.Dipin Singh  (12 years ago)

38.5 sq m

Area covered by goat = Pi*r^2/4
whre r= 7 m = length of rope

so area = (22/7)*7*7/4 = 38.5 sq m

Is this solution Helpfull? Yes (41) | No (6)  

Brij  (12 years ago)

@ Vinay,

Because the goat is tied to a corner of square plot.

It can only graze in 1/4 th of circle of radius equal to lrngth of rope inside that square plot.

I agree with Dipin.

Is this solution Helpfull? Yes (13) | No (2)  

arjun  (12 years ago)

ACTUALLY I SOLVED THE PROBLEM BT THANKS TO DIPIN A LOT..........

Is this solution Helpfull? Yes (8) | No (4)  

Vinay  (12 years ago)

y divided by 4...plz expln

Is this solution Helpfull? Yes (8) | No (3)  

Ramya  (9 years ago)

Area covered is 1/4 th of a circle
Its radius is 7

hence area of circle=pi*r*r

Area covered by goat=(pi*r*r)/4
So area=((22/7)*7*7)/4)=38.5 sq.m

Is this solution Helpfull? Yes (4) | No (1)  

swetha  (10 years ago)

actually area of square is a^2 but why we are using area of circle?

Is this solution Helpfull? Yes (3) | No (2)  

Pratik sharma  (9 years ago)

((22/7)*49)/4=38.5

Is this solution Helpfull? Yes (2) | No (2)  

anupama kumari  (9 years ago)

formula :a/360*(pi*r*r) where a is angle made by rope when tied to a corner of square
90/360*22/7*7*7=38.5m^2

Is this solution Helpfull? Yes (2) | No (2)  

Ankit  (8 years ago)

38.5, (90/360)(22/7)*7*7

Is this solution Helpfull? Yes | No   

Diksha Kacholiya  (8 years ago)

38.5 sq m
Area covered=(pi*r^2)/4
r=7

Is this solution Helpfull? Yes | No   

Nitin Maheshwari  (8 years ago)

sise of square=12
rope size=7
area graze by goat=3.14*7*7/4=38.5

Is this solution Helpfull? Yes | No   

Arnab Maity  (8 years ago)

so basically we have to find the area of the circle whose diameter is the length of the rope = 7m
Therefore radius = 7/2 = 3.5m
therefore area of the circle = Pi * (radius)^2 = Pi * (radius) * (radius) = 3.14 * 3.5 *3.5 = 38.5 sq.m

Is this solution Helpfull? Yes | No   

ANUPRIYA  (8 years ago)

since length of rope=7m
so it can graze only area covered by radius 7m./4
since,within this square only 1/4th area is present
so....area=22/7*7*7/4
=38.5 m2

Is this solution Helpfull? Yes | No   

reshma  (8 years ago)

a.38.5sq.m
(pi*r^2)/4
38.5

Is this solution Helpfull? Yes | No   

THUMMALA VINEESHA  (8 years ago)

area=pi*r*r/4
=3.142*7*7/4
=38.5 sqm

Is this solution Helpfull? Yes | No   

suchi  (8 years ago)

Why can't it grace outside the plot as in rectangular barn problems..............?

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