Latest TCS Aptitude Question SOLUTION: Q0. For a real number x, int(x) denotes integral part of x, that is int(x) is the largest integer less than or equal to x. The value of int(1/2)+int(1/2+1/100)+int(1/2+2/100)......

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Q0. For a real number x, int(x) denotes integral part of x, that is int(x) is the largest integer less than or equal to x. The value of int(1/2)+int(1/2+1/100)+int(1/2+2/100)......int(1/2+99/100)is

a)50
b)49
c)51
d)48

Asked In TCS ravikiran (10 years ago)

Solved RAKESH Read Solution (5)

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RAKESH  (10 years ago)

its right

X = int(1/2)+int(1/2 +1/100)+int(1/2 +2/100)......int(1/2 +99/100)

X = [ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] +
[ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2+99/100) ]

[ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] = 0 as, all terms less than 1

so, X = [ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2 +99/100) ]

= 1+1+1+... 50 times [from 50 to 99 = 50 times]

= 50

Is this solution Helpfull? Yes (33) | No (1)  

somya  (10 years ago)

X = int(1/2)+int(1/2 +1/100)+int(1/2 +2/100)......int(1/2 +99/100)

X = [ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] +
[ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2+99/100) ]

[ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] = 0 as, all terms less than 1

so, X = [ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2+99/100) ]

= 1+1+1+... 50 times

Is this solution Helpfull? Yes (3) | No   

ASHWANI KUMAR  (10 years ago)

answer shoul be a)50

Is this solution Helpfull? Yes (1) | No (2)  

RAKESH  (10 years ago)

X = int(1/2)+int(1/2 +1/100)+int(1/2 +2/100)......int(1/2 +99/100)

X = [ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] +
[ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2+99/100) ]

[ int(1/2)+int(1/2 +1/100)+...+int(1/2+49/100) ] = 0 as, all terms less than 1

so, X = [ int(1/2 +50/100)+int(1/2+51/100) ......+ int(1/2+99/100) ]

= 1+1+1+... 51 times

= 51

Is this solution Helpfull? Yes (1) | No (12)  

sanju  (10 years ago)

xpln it clrly

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