Latest TCS Aptitude Question SOLUTION: If X = ( 163 + 173 + 183 + 193 ), then X divided by 70 leaves a remainder of 1) 0 2) 1 3) 69 4) 35

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(#M40033826) TCS Numerical Ability question tcs Keep an EYE

If X = ( 163 + 173 + 183 + 193 ), then X divided by 70 leaves a remainder of


1) 0
2) 1
3) 69
4) 35

Asked In TCS sravani (10 years ago)

Unsolved Read Solution (4)

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RAKESH  (10 years ago)

X = 16^3+17^3+18^3+19^3
X = (16^3+19^3)+(17^3+18^3)

(x^n+y^n) is divisible by (x+y) for odd values of n

(16^3+19^3) is divisible by 16+19=35
(17^3+18^3) is divisible by 17+18=35

so,X = (16^3+17^3+18^3+19^3) is divisible by 35

also, X = ( 16^3 + 17^3 + 18^3 + 19^ 3 )is an even no. so, X is divisible by 2.
[since, E+O+E+O=E]

so, X is completely divisible by 35*2=70 & leaves a remainder 0

1) 0

Is this solution Helpfull? Yes (70) | No (2)  

sravani  (10 years ago)

here X = 16^3+17^3+18^3+19^3

Is this solution Helpfull? Yes (3) | No (5)  

Dharmendra Shukla  (9 years ago)

as we know that ->odd+odd=even
and hence the sum of given number is even and thus->even/even=even
and in the ans only 0 is even...
Ans:0

Is this solution Helpfull? Yes (3) | No (5)  

mohammed muaaz  (9 years ago)

using formulae of first n^3
f(n)=(n^2(n+1)^2 divided by 4)
put n=19 u get 36100
put n=15 u get 14400
36100-14400=21700
21700 divided by 70 gives remainder 0

Is this solution Helpfull? Yes (1) | No (3)  

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