Latest Miscellaneous Company Exam Aptitude Question SOLUTION: There are 4 boys and 3 girls seated in a row.Find the probability that all girls are together?

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(#M40035183) MISCELLANEOUS COMPAN Numerical Ability question time and distance Keep an EYE

There are 4 boys and 3 girls seated in a row.Find the probability that all girls are together?

Asked In Miscellaneous Company Exam NAGENDRA P (10 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

Saraswathy  (10 years ago)

Total No. of ways boys and girls can be seated = (4 + 3)! = 7! = 5040
No. of ways that girls seated together =>
consider 3 girls as a unit nd remaining 4 boys can be seated in any order...
So (1 + 4)! = 5! = 120
And those 3 girls can be seated among themselves in 3! ways => 6

[(ie) Let g1,g2,g3 be the girls... in 6 ways they can be seated together...
g1g2g3, g1g3g2, g2g1g3, g2g3g1, g3g1g2, g3g2g1]

So prob. that all girls are together => (120 * 6)/5040 => 1/7

Ans : 1/7

Is this solution Helpfull? Yes (17) | No (1)  

shaik ibrahim  (10 years ago)

((4+1)!)(3!)

Is this solution Helpfull? Yes (1) | No   

shree  (10 years ago)

7!
(4+1)!=120
120/7!
120/5040
1/42

Is this solution Helpfull? Yes (1) | No (1)  

Ann Theressa  (10 years ago)

Number of ways boys and girls can be seated = (4+3)! = 7!
Number of ways boys and girls can be seated with girls sitting together = (4+1)! = 5!

Probability that girls are together = 5!/7!
=1/42

Is this solution Helpfull? Yes | No (1)  

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