Latest Elitmus Aptitude Question SOLUTION: number 81A84B6c,where each of the letters A,B,C respresents a distinct digits,is divisible by each of the 5,8,9.Find the value of A+B? a)6 b)8 c)10 d)9

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(#M40037570) ELITMUS Numerical Ability question number system Keep an EYE

number 81A84B6c,where each of the letters A,B,C respresents a distinct digits,is divisible by each of the 5,8,9.Find the value of A+B?

a)6
b)8
c)10
d)9

Asked In Elitmus jitesh bhojwani (9 years ago)

Unsolved Read Solution (11)

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RAKESH  (9 years ago)

d) 9

81A84B6c is divisible by each of the 5,8,9.
c can be 0/5

B6c should be divisible by 8 so c can't be 5 => c = 0

8+1+A+8+4+B+6+c should be multiple of 9
=> 27+(A+B) should be multiple of 9
=> (A+B)= 9

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Abhishek  (9 years ago)

9 will be the answer,
in order to divide 81A84B6C by 5 last digit i.e C should be 5 or 0
but if we put as C=5 then number can't be divided by 8, so C will be 0
for divide number by 9 sum of number should be the multiple of 9 here
8+1+A+8+4+B+6+0=27+A+B
27 is the multiple of 9.
from option we see that none other then 9 are the multiple of 9
so answer should be 9

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ABHIJEET PANDEY  (9 years ago)

Ans.9
For divisibility by 5..C must be 0 or 5.
For divisibility by 8..B6C must be divisible by 8.
For divisibility by 9..sum of all digits must be divisible by 9.
Here..A=4,B=5 & C=0.

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sashank  (9 years ago)

c must be 5 or 0.... (27+a+b+c)/9 derfore if c=5...a+b must be 4 0r 13 0r 22 but they are no such options...so c=0..then (27+a+b)/9 a+b must be multiple of 9...so ans is 9

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pankaj  (9 years ago)

9

sum of 8+1+a+8+4+b+6+c / 9=0
27+a+b/9=0
so a+b must be 9

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RAHUL KUMAR  (9 years ago)

ans=9,
first 81A84B6C is divisible by 9 so 8+1+A+8+4+B+6+C must be divisible by 9
and is also divisible by 5 so C must be either 0 or 1
con 1) if c=5 the above number is not divisible by 9
con2) if c=5 the above no is divisible by 9 for A+B=9
so ans is 9

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shailendra sethiya  (9 years ago)

ans is 9 (d)

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tirupathi reddy  (9 years ago)

A= 7; B=2; c=0
c should be ----0
Bcoz 5 is divisible by no ends with 0 or 5
Last three digits must be divisible by 8 and 9
i.e.,720
A+B=9

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jitesh bhojwani  (9 years ago)

Rakesh you are right...

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nitesh  (9 years ago)

c=0/5...but c=0,because if we take c=5 then it will not devive by 8.so c=0
value of b=1/3/5/7/9 because last 3 digit should be divisible by 8.then
value of a=8/6/4/2/0...because for the divisibility of 9... the addition of whole digit should be divisible by 9...so a+b=9...

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shilpa  (7 years ago)

6 bcoz c is always zero becoz ccan't be 5 and only 0or 5 is divisibl by 5 and for division of 9 total should be divisible of 9

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