Latest A website Aptitude Question SOLUTION: Find the sum: √(1 + 1/12 + 1/22) + √(1 + 1/22 + 1/32) + ..... + √(1 + 1/20072 + 1/20082) a. 2008 - 1/2008 b. 2007 - 1/2007 c. 2007 - 1/2008 d. 2008 - 1/2007

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(#M40037970) A WEBSITE Category question Keep an EYE

Find the sum: √(1 + 1/12 + 1/22) + √(1 + 1/22 + 1/32) + ..... + √(1 + 1/20072 + 1/20082)

a. 2008 - 1/2008

b. 2007 - 1/2007

c. 2007 - 1/2008

d. 2008 - 1/2007

Asked In A website Liti (9 years ago)

Unsolved Read Solution (2)

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aishwary  (9 years ago)

We can calculate it by the formula of arithmetic progression that is
S=N/2[2a+(N-1)d].Therefore the correct answer is(a).

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shreeprakash  (7 years ago)

Take the first term:
√(1 + 1/12 + 1/22)
= √(1 + 1 + 1/4)
= √(9/4) = 3/2 =
2 - 1/2
Take the first two terms:
√(1 + 1/12 + 1/22) + √(1 + 1/22 + 1/32)
= 3/2 + √(1 + 1/4 + 1/9)
= 3/2 + √(49/36)
= 3/2 + 7/6
= 8/3
3 - 1/3
Similarly:
√(1 + 1/12 + 1/22) + √(1 + 1/22 + 1/32) + ..... + √(1 + 1/20072 + 1/20082)
= 2008 - 1/2008
So option (a) is correct

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