Latest Elitmus Aptitude Question SOLUTION: virat & anushka starts running in clockwise direction at the same time and ratio of their speed is 5:3. it takes 0.5km to complete one round then how much distance will virat cover

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virat & anushka starts running in clockwise direction at the same time and ratio of their speed is 5:3. it takes 0.5km to complete one round then how much distance will virat cover when he crosses anushka 6th time?

Asked In Elitmus Gaurav Malhotra (9 years ago)

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saira fatma  (9 years ago)

7.5km
time of one round=0.5/2x
time of 6 round=0.5*6/2x=1.5/x
distance covered till 6round by virat=1.5*5x/x=7.5km

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DIMPLE SINGH  (9 years ago)

ratio of speed=5:3

let speed of Virat= 5ms
let speed of Anushka =3ms

lenth of circular path= 0.5km = 500m

Time taken by Virat to complete 500m = 100sec

Virat will cross Anushka after every 250sec

for 6th cross:

total time= 6*250 sec
= 1500 sec
distance covered in 1500 sec = (1500*500)/100 m
=7500 m
= 7.5 km

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raushan kumar  (9 years ago)

ans is 3.5 km. bcoz 6 meet in totall 7 round .

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Pratik Keshri  (9 years ago)

time taken by virat to cover 1 round is 0.5/5=0.1hr
in 0.1hr anushka has coverd 0.1*3=0.3km
let dist is x from 0.3km when they meet first ,then equating time for both i.e 0.3+x/5=x/3 ,we getx=0.75km
it means 0.25km from starting point and virat has covered 0.5+0.25=0.75km in first meet .
therefore in 6th meet virat has covered 0.75*6=0.45km

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DIMPLE SINGH  (9 years ago)

its a repeated question
answr is 7.5km

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Niranjan C  (9 years ago)

Ans is 10.
Explanation: 1. Speed=distance/time
2. therefore the ratio of speed given is 5/3
3. virat speed 5=(.5)/x. where x is time taken
4. anushka speed 3=(.5)/y where y is time taken by anushka
5. Dividing eq3 by eq4 : 5/3=y/x
6. therefore by eq5 we can see that while anushka completing 3 rounds, virat completes 5 rounds so
while anushka completing 6th round, virat would have completed 10th round.

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pranav khandelwal  (9 years ago)

Ratio of speed=5:3
Virat's speed=(5/8)x;
Anushka's speed=(3/8)x;
Time taken by virat for one round= (500)/(5x/8);
=>800/x;
Time by anushka for one round=(500)/(3x/8);
=>4000/(3x)
Lcm to dind out which one meets first=6400/(3x)
the distance covered by virat to meet first time=5x/8*6400/(3x)=4000/3 m
6th time=(4000/3)*6=8000m
therefore rouund=16th round ANS
With Regards
Pranav Khandelwal

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DIMPLE SINGH  (9 years ago)

sorry
(it should be m/s not ms)
speed of virat = 5m/s
speed of Anushka = 3m/s

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pranav khandelwal  (9 years ago)

sorry by mistake
the lcm would be= 4000/x
distance=5x/8*4000/x=2.5km
for 6th round=2.5*6=15km

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Abhishek Sa  (9 years ago)

speed ratio=5:3
virat=5x
anush=3x

t1=0.5/5x=500m/5x=100/x
t2=500/3x

t(diff)= 500/3x - 100/x =200/3x
difference distance btween two = 200/3x * 2x = 400/3

anushka travelling 6 tyms distance covered = 1000m
difference betwween virat and anushka wen anushka completes 6th tym = 6*400/3 =800m

total distance covered by virat wen he crosses anushka 6th tym = 1000+800 m
=1.8km

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