Latest TCS Aptitude Question SOLUTION: what is the remainder when 789456123 is divided by 999

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what is the remainder when 789456123 is divided by 999

Asked In TCS SHUBHAM SONI (9 years ago)

Solved ranjan kumar Read Solution (18)

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Read Solution (18) :

ranjan kumar  (9 years ago)

there is a simple trick for 99 or 999..u have to add the digits from right side for 99 you will select the last 2 digits and add with next two last digits and go on..similarly for 999 u will add last three digits then its next two last digits and so on..

so you will get 123 + 456 +789 =1368 again select last 3 and add them u will get 368 + 001 i.e 369 anssssssssss

Is this solution Helpfull? Yes (114) | No (3)  

RAKESH  (9 years ago)

369

789456123 / 999
789456123 / 9*111
87717347 / 111 => rem = 41
we have cancelled it by 9
reqd remainder = 9*41 = 369

Is this solution Helpfull? Yes (22) | No (6)  

karthikeyank  (9 years ago)

Ans:369
789+456+123=1368/999=1368-999=369 remainder

Is this solution Helpfull? Yes (18) | No (1)  

Himadri Mitra  (9 years ago)

Ans is 369

789+456+123=1368
again...1+368=369

Is this solution Helpfull? Yes (2) | No   

rameshnaidu  (9 years ago)

789+456+123=1368
1368/999=369

369 is the answer

Is this solution Helpfull? Yes (1) | No (2)  

sahitya  (9 years ago)

@karthikeyank: can you please explain, how did you add the numbers,
789+456+123=1368, its all the same number.

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Ravikant  (9 years ago)

789+456+123=1368
now
1368%999=369
so,369 is the ans.

Is this solution Helpfull? Yes (1) | No (1)  

Ravikant  (9 years ago)

see... the given number is divided by 3 digit number thats y we break this no. in 3 digits from right to left.. n add them. n then as follows
789+456+123=1368
now
1368%999=369
so,369 is the ans.

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karthikeyank  (9 years ago)

@SAHITYA:
ACTUAL QUESTION IS 789456123

1368 IS SUM OF 789+456+123

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vignesh  (9 years ago)

@karthikeyan why you select 789 ,456,123 and y u add it all ? is there any rule or method

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khushboo tomar  (8 years ago)

add the digits from right to left in the pairs of three digits and then add them..123+456+789+1368.. now again... 1+368=369..hence it the answer

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Ravi Kudumu  (8 years ago)

789456+123=789579==>789+579=1368==>1+368=369

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Nitin Maheshwari  (8 years ago)

789456123/9*111=87717347/111=792462( 41 is remainder)
41*9=369

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Subhajit Dutta  (8 years ago)

123+456+789=1368
1368 % 999 =369(ans.)

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Raghvendra Pandey  (8 years ago)

789+456+123=1368
1368%999=369

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Rajanikanta Pradhan  (8 years ago)

one formula is there
789+456+123=1368
1368/999=369

369 is the answer

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SHAKTI SINGH  (8 years ago)

In case if you want to find 12345123451234512345.........upto n times by any three digit no. then divide n by no of digit being repeated and multiple by sum of group of 3 digits of given no. find result and if result is carrying more than 3 digits then again make group of 3 and again sum them until you get less than or equals to 3 digit no.
then take (resultant no)modulo(given three digit no.)= it is your result

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shanu chauhan  (8 years ago)

369

789456123 / 999
789456123 / 9*111
87717347 / 111 => rem = 41
we have cancelled it by 9
reqd remainder = 9*41 = 369
Read more at http://www.m4maths.com/38590-what-is-the-remainder-when-789456123-is-divided-by-999.html#at_pco=smlwn-1.0&at_si=55dc10b6a718d8ab&at_ab=per-2&at_pos=0&at_tot=1#w8bR7KG14Gpl9R77.99

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