Latest Elitmus Aptitude Question SOLUTION: N= (323232 ... 50 digits ) base 9 Find the remainder when N is divided by 8 Options 1,-1,0,3

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(#M40038710) ELITMUS Numerical Ability question Keep an EYE

N= (323232 ... 50 digits ) base 9
Find the remainder when N is divided by 8
Options
1,-1,0,3

Asked In Elitmus Pratik Keshri (9 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

dayanand giri  (9 years ago)

9^32323232.....50digits
first divide 9 by 8 remainder should be 1
so 1^32323232.....50 digits divided by 9 remainder should be 1.
than answer must be 1.

Is this solution Helpfull? Yes (36) | No (3)  

akash verma  (9 years ago)

there is a formula i.e
(a+1)^n/a always gives a remainder of 1
so , 9^323232..../8 === (8+1)323232.../8 so remainder == 1

Is this solution Helpfull? Yes (9) | No (2)  

Uma  (9 years ago)

How you took 9^3232..... Pls explain.

Is this solution Helpfull? Yes (3) | No   

ajit kumar sharma  (8 years ago)

N=(323232...50 digits)base9 =(3*9^49+2*9^10+..............3*9+2*9^0)base10
remainnder will be=(3*9^49+2*9^10+..............3*9+2*9^0)/8=(3+2+3+2+3.....+3+2 )8=(25*3+25*2)/8=5
ans will be 5......but for answer it may have mistakenly written 3
because 3 will be anser when number of 3 will be 25(25*3)+numbers of 2 will be 24(24*2)=(75+48)/8=3......
i dont know wheter answer is wrong or my solution.......thnx if somebody go through my explanation plzzz make me correct if i am wrong.....thanku

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Siri  (9 years ago)

use remainder theorem
f(x)/(x-a)=f(a)
x=9 , a=1
9^32323232/(9-1)=1^32323232 which is equal to 1

Is this solution Helpfull? Yes (2) | No   

abhishek maini  (9 years ago)

@dayanand how base 9 becomes 9^323232....upto 50

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suman kumar  (9 years ago)

0 be the answer

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sandeep kumar  (9 years ago)

@DAYANAND ,AKSASH
would u plz explain how base OF any number iE nine IN THIS CASE becomes 9 power somthing.........

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hriday  (8 years ago)

8 convert on base 9=8
(3232--------3232)%8=0

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rajveer singh  (8 years ago)

i think the reminder would be 0. Because if we convert (8) with base 10 to (8) with base 9 and then if we divide 3232323232......50times with this then the reminder would be 0.

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aditi yadav  (8 years ago)

50 digits i.e 25 pair of 32.
and in base 9 ,the divisibility rule for 8 is sum of digits. so, N=(25*3+25*2) as,[ 3 and 2 from 32]
and convert 25 to base 10 =23
nw it will be like N= (23*3 +23*2)in base 10
converting back to base 9 = 137
so sum of the digits nw will be 1+3+7 =11 in base 9
11/8= 3 .
so ans is 3 as remainder.

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aditi yadav  (8 years ago)

sry cn't specify as rule ,consider it as divisibility check for 8 i.e sum of digits

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