Latest TCS Aptitude Question SOLUTION: a cow and a horse are bought for 200000.the cow is sold at a profit of 20% and horse at a loss of 10%.the overall gain is 4000.the cost price of the cow..?? 70000 80000 120000 1300

• Placement Papers
• /
• TCS
• /
• Category

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40038764) TCS Category question Keep an EYE

a cow and a horse are bought for 200000.the cow is sold at a profit of 20% and horse at a loss of 10%.the overall gain is 4000.the cost price of the cow..??
70000
80000
120000
130000

Asked In TCS ranjan kumar (9 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (3)   (2) Submit Your Solution

Read Solution (5) :

Chandrashekhar  (9 years ago)

Cost price of cow is ₹80000.
Let us assume the C.P of cow = x
C.P of horse = y;
Then according to the given condition x+y=200000 --------(1);

Also the S.P of Cow = 1.2x
S.P of horse = 0.9y
So total S.P = 1.2x+0.9y

Given,
(1.2x+0.9y)-(x+y) = 40000 --------(2)

Now two variable two equation, on solving we get x=80000

Is this solution Helpfull? Yes (10) | No   

hercules  (9 years ago)

let x be CP of cow
profit from cow-loss from horse = 4000
0.2x - 0.1(200000-x) = 4000
x = 80000

Is this solution Helpfull? Yes (5) | No   

nisha sharma  (9 years ago)

using alligation & mixture,
p%=4000*100/20000=2%
20%_______2%_______-10%
12 18
hence ratio is 2:3
total sum of ratio=2+3=5
cp of cow=2*200000/5=80000
hence answer is 80000

Is this solution Helpfull? Yes (5) | No   

Niveditha Ravichandran  (9 years ago)

cp of cow and horse = 200000
p% of cow = 20%
l% of horse = 10%

let cp of cow = x
cp of horse = 200000-x

overall gain = 4000
therefore sp - cp =4000 --> 1

sp = 120% of x + 90% of (200000-x)
= 6x/5 + 180000 - 9x/10
= 3x/10 + 180000
substitute sp in eqn 1 and cp=200000(given)

3x/10 + 180000 - 200000 = 4000
3x/10 - 20000 = 4000

solving x= 80000 (ans cp of cow)

Is this solution Helpfull? Yes (4) | No   

Akshay Gupta  (9 years ago)

ans 80000
let cost price of cow =x and horse =y
then x+y=200000
now cow sold at 20% profit and horse at 10% loss
so 6x/5 + 9y/10 = 204000
therefore 12x+9y=2040000
solving these two equations we get price of cow x = 80000

Is this solution Helpfull? Yes (2) | No   

Please Login to Read Solution.