Latest TCS Aptitude Question SOLUTION: How many 8 digits numbers can be formed with repetition by using 1,2,3,4,5 which are divisible by 4

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How many 8 digits numbers can be formed with repetition by using 1,2,3,4,5 which are divisible by 4

Asked In TCS sowjanya (9 years ago)

Unsolved Read Solution (6)

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RAKESH  (9 years ago)

for divisible by 4 the last two digit should be 12,24,32,44,52 ( 5 WAYS )

rest 6 places can be filled in 5*5*5*5*5*5 = 5^6 ways

so, total no. formed = 5 * 5^6 = 5^7

Is this solution Helpfull? Yes (37) | No   

Kuttyma   (9 years ago)

Pls state the correct ans .......... All r providing ur own ans. So state the correct ans

Is this solution Helpfull? Yes (4) | No (3)  

rohit kumar raju  (9 years ago)

the way of forming 8 digit no by using 5 digit and repitation is allowed r
5*5*5*5*5*5*5*5=5^8
but no should be divisible by 4, it is possible only when last 2 digit be divisible by 4.
first find out 2digit no which divisile by 4 r 12 24 32 44 54 only so ans is
5*5^6

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abdul quadir khan  (9 years ago)

6*(5^6)
As last 2 digits should be divisible by 4 so as to have divisible by 4

Is this solution Helpfull? Yes | No (2)  

nmtsaikumar  (9 years ago)

12,24,32,44,52 are the only numbers at last two positions satisfying the given condition. Remaining digits can be written in 5^6 ways
Hence, total no. of ways = 5 * 5^6

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Rajanikanta Pradhan  (8 years ago)

5_5_5_5_5_5_ _
12
24
32
52
44
So 5^6*5
=5^7

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