Latest TCS Aptitude Question SOLUTION: In a reading room of a library there are 22 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. In each table different numbers of people are

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In a reading room of a library there are 22 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. In each table different numbers of people are seated. If in all there are 36 readers how many reading spots will be left out without at least 1 reader?

a) 8
b) 12
c) 16
d) None of these

Asked In TCS Pradeep Saw (9 years ago)

Unsolved Read Solution (17)

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Read Solution (17) :

shaileshwar.s  (9 years ago)

Since at least there can be 1 reader in a table so the following case is possible
1st table- 9 members
2nd table- 8 members
3rd table- 7 members
4th table- 6 members
5th table - 5 members
6th table -1 member
therefore 9+8+7+6+5+1=36 and no. of tables are 6. so, no. of remaining tables are 22-6 = 16(ans).

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MUNISH YADAV  (9 years ago)

1,2,3,4,5,6,7,8, rest all empty. i.e. 22-8=14

Is this solution Helpfull? Yes (7) | No (6)  

Nayab Qamar  (9 years ago)

d - non of these... coz I guess answer willb 18

Is this solution Helpfull? Yes (3) | No (4)  

Puja singh  (9 years ago)

sorry frnds answer is 14 so option d is correct

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Avantika Kumari  (9 years ago)

14. so the answer is d

Is this solution Helpfull? Yes (3) | No   

Kethineni Vinodh  (9 years ago)

different no of people means

assume 9+8+7+6+5+1=36

so 22-6=16

Is this solution Helpfull? Yes (3) | No   

N.ANNUSHYA  (9 years ago)

Ans:d)None of these
readers are arranged in the each reading spots 1,2,3,4,5,6,7,8
hence 8 tables are filled.(36 readers)
22-8=14

Is this solution Helpfull? Yes (2) | No (1)  

shaileshwar.s  (9 years ago)

Since at least there can be 1 reader in a table so the following case is possible
1st table- 8 members
2nd table- 7 members
3rd table- 6 members
4th table- 5 members
5th table - 4 members
6th table - 3 members
7th table - 2 members
8th table - 1 member
therefore 8+7+6+5+1=36 and no. of tables are 5. so, no. of remaining tables are 22-5 = 17(ans).

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Proloy Mukherjee  (9 years ago)

16
As let's consider worst case scenario
9 on t1
8 on t2
7
6
5
1 so

16 tables remain

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raviteja  (9 years ago)

since different number of people are seated since atleast1 reader should not be common 1 reader should not present as common in each reading spot---=arrange 9 difeerent people in 4 reading spots =9*4=36 and remaining are 22-4=18 so d is answer

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rishabh patel  (9 years ago)

9,8,7,6,5,1 so 6 table is filled ans is 22-6=16 option 'c'

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Puja singh  (9 years ago)

answer is 16. :)

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MUNISH YADAV  (9 years ago)

Sum of readers is 36.
Sum of 1,2,3,4,5,6,7,8 = n(n+1)/2 = 8*9/2 = 36

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muthukumaran  (9 years ago)

ans:C (16)

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rajesh goud  (9 years ago)

d)22-8=14
total 22, 8 occupied

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avni sorniya  (9 years ago)

1st table- 8 members
2nd table- 7 members
3rd table- 6 members
4th table- 5 members
5th table - 4 members
6th table - 3 members
7th table - 2 members
8th table - 1 member
so 8+7+6+5+4+3+2+1=36.
now 22-8=14 ans.

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sharmilaravi  (9 years ago)

ans is: 16
assume in 1st spot there is 1 reader,2nd spot there is 2 readers , similarly until 8 spots there will be a total of 36 readers.
22-8=16
hence 16 is the ans

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