Latest TCS Aptitude Question SOLUTION: last two digit of 123^(!123)

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(#M40039012) TCS Category question Keep an EYE

last two digit of 123^(!123)

Asked In TCS SHUBHAM SONI (9 years ago)

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Sujithra  (9 years ago)

If gcd(a,M) == 1 then
a^ phi(M) % M = 1
lets us consider M = 100
phi(100) = 40
123^40 % 100 = 1

123! is multiple of 40.
So 123^(123!) = 1

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swap  (9 years ago)

01 is the answer
last 2 digit of 23^1 =23
last 2 digit of 23^2 =29
last 2 digit of 23^3 =67
last 2 digit of 23^1 =23
last 2 digit of 23^4 =41

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last 2 digit of 23^20 =01
last 2 digit of 23^21 =23
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so 123! is multiple of 20
therefore last 2 digit of 23^(123!) = 01

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gautam gaurav  (9 years ago)

123^4*even no!
for last two digit (23^4)^even no!
=41^even no!
=01
so ans is 01

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raviteja  (9 years ago)

how do we know tthat 123!is even @rakesh

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