Latest TCS Aptitude Question SOLUTION: In how many ways can we distibute 7 different objects to 3 different person so that either one or two does not get any object? Plz explain me this problem

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In how many ways can we distibute 7 different objects to 3 different person so that either one or two does not get any object?
Plz explain me this problem

Asked In TCS Priyanka Gaikwad (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

shaurya neel  (9 years ago)

1st take that 2 of them doesn't get any of the objects...

there are 3 persons so.....

7 , 0 , 0 and this can be of 3 ways....like 0,7,0...0,0,7

now one of the person doesn't get any object....
it can be done by following way....

6,1,0------3! ways
5,2,0-------3! ways
4,3,0--------3! ways..

so total ways =3! + 3! + 3! +3 = 21 ways...

Is this solution Helpfull? Yes (76) | No (17)  

miraj ansari  (9 years ago)

here by prob we can say that if any 2 dont get any obj.total obj goes to 3rd person in 3 way.
if 1 of them dont get object then 7 object goes to 2 person

(1,6)=7c1

(2,5)=7c2

(3,4)=7c3

(4,3)=7c4

(5,2)=7c5

(6,1)=7c6

total 7c1+7c2+7c3+7c4+7c5+7c6=126

for 2 person two way=2*126=378

3rd person get the object in 3 way

so tatal =3+378=381 way Ans

Is this solution Helpfull? Yes (34) | No (22)  

sri krishna  (9 years ago)

here there are two cases , either or two wont get any object
case:1
two wont get object i.e,any of three can get all objects,therefore 3 ways.
case2:
seven must bedistributed among two it can distributed in 6 ways i.e (6,1) (1,6)
(4,3) (3,4) (5,2) (2,5) besides any of three can be selected
so total no of ways in second case is 3*6=18 ways
adding both cases:- 3+18 = 21 ways

Is this solution Helpfull? Yes (7) | No (5)  

devika chaudhari  (9 years ago)

381 is the correct answer

Is this solution Helpfull? Yes (4) | No (5)  

ganesh thakur  (9 years ago)

7c3-(7c1+7c2)

Is this solution Helpfull? Yes (2) | No (6)  

diksha khurana  (9 years ago)

(3)^7-(2^7+1^7)=2058

Is this solution Helpfull? Yes (1) | No (4)  

deepak  (9 years ago)

since it is possible that no object to one or two of them .we would have 3 choice for giving each object hence 3*3*3*3*3*3*3=2187

Is this solution Helpfull? Yes (1) | No (3)  

Pratik sharma  (9 years ago)

Formula is :- Combination of n object taken r at a time when k object never chosen
(n-k)C(r)

so there are two cases for 1 and for 2
thus (6)C(3)+(5)C(3)=30

Is this solution Helpfull? Yes (1) | No (2)  

Khushi   (9 years ago)

if 1 and 2 doesnt get any object then the 3rd person will get that in3 ways -
007,700,070.
one one of the person will not get any object
if 1st person doesnt get the object-
0,6,1 or 0,1,6
0,4,3 or 0,3,4
0,2,5 or 0,5,2
3!*6=36
accordingly for 2nd and 3rd person
36 and 36
so the total no of way is
3*36+3= 108+3 =111

Is this solution Helpfull? Yes | No (3)  

Basil Sufyan  (9 years ago)

147
3c1*7c2 + 3c2*7c1

Is this solution Helpfull? Yes | No (2)  

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