Latest TCS Aptitude Question SOLUTION: Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125.

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(#M40039403) TCS Logical Reasoning question Keep an EYE

Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125.

Asked In TCS SUDIP ROY (9 years ago)

Unsolved Read Solution (25)

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Read Solution (25) :

AARVI MISHRA  (9 years ago)

15=5*3,32=2*2*2*2*2,25=5*5,22=2*11,40=2*2*2*5,75=5*5*3,98=2*7*7,112=2*2*2*2*7,125=5*5*5;
there are 9 (5*2) pairs so there are 9 zeroes

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Ram  (9 years ago)

3*5*2^5*5^5*2*11*2^3*5*3*5*5*2*7*7*2^4*7*5^3
no of zeros= minimum no of (2,5)
no of zeros=9

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karthikeyank  (9 years ago)

Ans is:9
There are 9 pairs in following from(2,5)
3*5,2^5,5^2,2*11,2^3*5,5^2*3,2*29,2^4*7,5^3

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Anshu pathak  (9 years ago)

multiply all the unit places of all numbers. then we get 1112424000000000. so number of zeros are 9.

Is this solution Helpfull? Yes (2) | No (6)  

jyoti kothiyal  (9 years ago)

to do such a question we have to find the no of 10's in the expression. in each & every case finding the no of 5's will be sufficient bcoz each 5 is followed by a 2 thus making it 10. in this expression there are 9 no of zeros by prime factorisation

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anusha  (9 years ago)

multiply all the unit places of all numbers .then we get 400000.so the number of zeros are 5.

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md wasim akhtar  (9 years ago)

ans 9
no. of 5's is 9
so no. of zeroes will be 9

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Nomendra Sinha  (9 years ago)

@ anchal gupta
compare power of 2's(i.e. 14) and 5's(i.e. 9)
Minimum of (9,14)
so 9 is ans.

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Nomendra Sinha  (9 years ago)

@ Jyoti Kothiyal
Finding no. of 5 is not sufficient
Exa- 42*75

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gummaidvijaya  (8 years ago)

take last two nmbers112-2&125-5 thi gives 10 which also gives 0
like wise 8*5=40which also gives 0
'' 5*2=10 '' 0
'' 5*2=10 '' 0
as 40 consists a zero(0).
so in TOTAL OF FIVE ZERO'S

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dheeraj sachdeva  (9 years ago)

no. of zeros= 9

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bhanu shakya  (9 years ago)

there are 158 wheels in a parking.some are cycles and some are cars....how many cycles are there in parrking??

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virendra tiwari  (9 years ago)

ans 9
total no of 5

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aneel  (9 years ago)

we get 9 5s then there will be 9 0s

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anchal gupta  (9 years ago)

minimum of(2,5)
what's mean?
explain it

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debayan khanra  (9 years ago)

no of zero is 9
15*32*25*22*40*75*112*125=3*5*2^5*5*2*11*2*4*5*2*5*5*3*7*7*2*2^4*7*5*5*5
so no of 5=9 and we know 0 is produced multiplication of 2 and 5..

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ANKIT SHARMA  (9 years ago)

there are 8 5's
Hence 8 zeros

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Aastha  (9 years ago)

no of zeros will be 9 as
there are total number of 5 in the given expression is 9.
on multiplying these with 2,we get 9 zero

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Tanvir Sarkar  (9 years ago)

0, 6, 29, 63,124?

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Ravinder singh  (9 years ago)

count the no of 5's by doing the prime factors of above numbers . answere= 9

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harika  (9 years ago)

(5*3)*(2^5)*5^2*2*11*5*2^3*5^2*3*2*7^2*2^3*7*2*%^3
total no.of (2*5)pairs is the no.of 10's

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Mohammed faiz ahmed  (9 years ago)

there are total of 9 5's and >9 2's
so there are total of 9 zeroess

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smriti shikha  (9 years ago)

5^9 dats y 9 zeroes

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mounika  (9 years ago)

6 0's i think

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sivaranjani  (9 years ago)

if 5 * 2 = 10. so one pair of 5 and 2 get one zero. find the no of 5 and 2 pair. so ans is 9

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