Latest TCS Aptitude Question SOLUTION: A owes B, Rs. 1120 payable 2 years hence and B owes A, Rs. 1081.50 payable 6 months hence. If they decide to settle their accounts forthwith by payment of ready money and the rate

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A owes B, Rs. 1120 payable 2 years hence and B owes A, Rs. 1081.50 payable 6 months hence. If they decide to settle their accounts forthwith by payment of ready money and the rate of interest be 6% per annum, then who should pay and how much.

Asked In TCS Pradeep Saw (9 years ago)

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Shaik Jahangeer Basha  (9 years ago)

A owes=P.w. of Rs.1120 due 2 years hence
=Rs[1120*100/(100+(6*2))]
=1000
B owes=P.w. of Rs.1081.50 due 1/2 years hence
=Rs[1081.50*100/(100+(6*(1/2)))]
=1050
B must pay Rs.50 to A

Is this solution Helpfull? Yes (7) | No (1)  

Abhishek Kumar Yadav  (9 years ago)

we are given here the present worth of A and B.
present worth(P.W) is the total amount to be paid i.e (SI+Principal)
So Case 1:In case of A
PW=1120,so SI=1120-Principal..now calculate the principal from eq of SI i.e
1120-P=(P*6*2)/100,s0
P in case of A is 1000.

similarily,P in case of B is 1050..

so B must pay rs.50 to A

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supriya  (9 years ago)

@ shaik plz explain

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Nupur Pachunkar  (9 years ago)

PW for A=100*1120/100+(6*2)= Rs 1000.
PW for B=100*1081.5/100+(0.5*6)= Rs 1050.
Hence B has to pay A (1050-1000) i.e Rs 50.

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anchal gupta  (9 years ago)

SHALIK which formula u have used to calculate the PW

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Sanjit Kumar Sharma  (9 years ago)

A owes=P.W of Rs. 1120 due 2 years hence
=Rs. [(1120*100)/(100+(6*2))]= Rs. 1000
B owes =P.W of Rs. 1081.50 due 1/2 years hence
=Rs.[(1081.50*100)/(100+(6*1/2))]=Rs. 1050
therefore, B must pay Rs. (1050-1000)= Rs. 50 to A.

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mounika  (9 years ago)

wt is p.w i can't understand explain clearly nd wt's d formula

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soumya  (9 years ago)

can u plz explain it again as to what is p.w.?

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aman sharma  (9 years ago)

p.w is nothing just total amount interest+principal

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