Latest TCS Aptitude Question SOLUTION: a,b,c,d,e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299 then a+b+c+d= ?

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a,b,c,d,e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299 then a+b+c+d= ?

Asked In TCS ranjan kumar (9 years ago)

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Read Solution (8) :

Ram  (9 years ago)

2299 = (-11)*11*19*(-1)*1
75-a= -11
75-b=11
75-c=19
75-d= -1
75-e=1
a=86,b=64,c=56,d=76,e=74
a+b+c+d+e=356
a+b+c+d=270 or 292 or 300 or 280 or 182
since any one of the 5 numbers can be a,b,c,d

Is this solution Helpfull? Yes (19) | No (3)  

Abhirup Sarkar  (9 years ago)

2299=11*11*19*1*1
75-a=11; a=64
75-b=11; b=64
75-c=19; c=56
75-d=1; d=74
75-e=1; e=74
a+b+c+d=258

ans=258

Is this solution Helpfull? Yes (18) | No (8)  

KAZI AMINUDDIN ZAMAN  (9 years ago)

ADWAIT SATHE, brother do the LCM of that given number and u get 11 * 11 * 19 * 1. And since distinct numbers are told in qstn you can give negative sign to one of the same numbers occuring twice. Hope that answered your question.

Is this solution Helpfull? Yes (6) | No (1)  

Adwait sathe  (9 years ago)

2299 = (-11)*11*19*(-1)*1

how did this come ? please explain . which book to refer for these kind of problems ?

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karthikeyank  (9 years ago)

Ans is:280
(75-a)(75-b)(75-c)(75-d)(75-e)=2299
a,b,c,d, are distinct numbers
11,-11,19,1
64+86+56+74=280

Is this solution Helpfull? Yes (3) | No (2)  

sreekanth  (9 years ago)

2299 = 11×11×19×1×1=11×−11×19×−1×1=
Two of the terms in the given expression should equal to 1. As all the digits are distinct, two of the terms should be negative.
One possible solution = (75 - 64)(75 - 56)(75 - 86)(75 - 74)(75 - 76)
Then a + b + c + d + e = 64 + 56 + 86 + 74 + 76 = 356
But as the sum of only 4 terms was asked, we have to subtract one term.
So given answer can be one of 292, 306, 270, 282, 280.I just copied the solution from campusgate.com..hope its useful

Is this solution Helpfull? Yes (2) | No (1)  

KARTHIKA  (9 years ago)

how 11,-11,19,-1 and 1 are taken.anybody please reply

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swarnima  (9 years ago)

2299=11*11*19*1*1

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