Latest TCS Aptitude Question SOLUTION: A sum is sufficient to pay either George age for 15 days or marks wage to 10dayshow long together?

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A sum is sufficient to pay either George age for 15 days or marks wage to 10dayshow long together?

Asked In TCS mahendran (9 years ago)

Solved ANITHA RAMASAMY Read Solution (11)

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ANITHA RAMASAMY  (9 years ago) Best Solution

George one day work is (1/15)
Marks one day work is (1/10)
G+M=(1/15)+(1/10)=(1/6)
6 is the answer

Is this solution Helpfull? Yes (14) | No (2)  

shahrukh  (9 years ago)

i dont think its a tcs question

Is this solution Helpfull? Yes (9) | No (8)  

KARTHIKEYAN  (7 years ago)

A certain sum of money is sufficient to pay either George wages for 15 days or Mark wages for 10 days .For how long will it be sufficient if both George and Mark work together ?
a)5 b)6 c)9 d)8
This is the proper question?

Is this solution Helpfull? Yes (9) | No   

monisha  (9 years ago)

george work 1/15
marks work 1/10
work together so (1/15)+(1/10)=(1/6)
then 6 will be the answer

Is this solution Helpfull? Yes (4) | No (1)  

Juhi Sinha  (9 years ago)

Please write question clearly

Is this solution Helpfull? Yes (1) | No   

amar  (6 years ago)

Ans=6days
Total work= Geroge and marks is 60 work. i.e LCM of Geroge and Marks
now George does 2Work/day.
marks does 3work /day
if both work G+M=5work/day
so total 30 work=30/5=6 days..

Is this solution Helpfull? Yes (1) | No   

Ashwin Patidar  (7 years ago)

Correct Question:-

A certain sum of money is sufficient to pay either George's wages for 15 days or Mark's wages for 10 days. For how long will it suffice if both George and Mark work together?

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kishor Patil  (5 years ago)

consider sum is lcm(15,10) =30rs
George one day 30/15=2rs
marks one day 30/10=3rs
total one day pay=2+3=5rs
30/5=6 its sufficient for 6days

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MURUGANANDHAM R  (5 years ago)

george 1 day work is=1/15
mark 1 day work is=1/10
together=(1/15)+(1/10)
=5/30
=6
because 6 is the answer

Is this solution Helpfull? Yes | No   

chirag  (5 years ago)

This question is repeated in TCS Ninja 2018, :) !.

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Ritendra Pratap Singh  (4 years ago)

f(2018)=f(2x1009)=f(504+1)=f(2x252+1)=f(252)+1
f(252)=f(2X126)=f(126)=f(2X63)=f(63)=f(2X31+1)=f(31)+1
f(31)=f(2X15+1)=f(15)+1
f(15)=f(2X7+1)=f(7)+1
f(7)=f(2X3+1)=f(3)+1
f(3)=f(2X1+1)=f(2)+1
f(2)=f(2X1)=f(1)
f(1)=f(2X0+1)=f(0)+1=1

So we have, f(1)=1
f(2)=1
f(3)=1+1
f(7)=2+1
f(15)=3+1
f(31)=4+1
f(252)=5+1
f(2018)=6+1=7 Ans

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