Latest TCS Aptitude Question SOLUTION: a,b,c are non-negative integers such that 20a+30b+31c=365, then a+b+c =?

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a,b,c are non-negative integers such that 20a+30b+31c=365, then a+b+c =?

Asked In TCS vivek gupta (9 years ago)

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Soumalya Chakraborty  (9 years ago)

vivek i think the question will be 28a+30b+31c=365
now in a normal(non-leap year) year we have month having 28 days 1, 30 days 4 months, 31 days 7. so a+b+c=12

Is this solution Helpfull? Yes (15) | No (1)  

bongu divya  (9 years ago)

12
per yr 365 days
so 12 months

Is this solution Helpfull? Yes (3) | No (2)  

Nischay Jain  (9 years ago)

all brothers.you are fully wrong.the question cant be changed according to your suits in any competetive exams.so please solve it.be an an ENGINEER,not a RATTU TOTA>
according to the question the solution is following:
20a+30b+31c=365
20a+30b+31c=20x3+30x5+31x5
compaRING TWO SIDES WE GET A=3,B=5,C=5 now,a+b+c=13.

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GOPI Raghav  (9 years ago)

answer is 90 based on the year concept

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surbhi disawal  (9 years ago)

its not 20a it should be 28a
so according to our calender
a+b+c=12

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sunit tiwari  (9 years ago)

This is tricky ques:
here a,b,c are the months and total days are 365.
therefore a=1,b=4,c=7.
and sum is 12.

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KeerthanaDevi.S  (9 years ago)

20a+30b+31=365
a=1
b=6
c=5 so totaly 12 months.

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ANIMESH GORAI  (9 years ago)

12 or

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Gurukarthick  (9 years ago)

The given question is calendar based.We have to take calculation of days in a particular month
28--Feb(a=1)
30-apr,june,sep,nov(b=4)
31-Jan,March,May,July,Aug,Oct,Dec(c=7)
The question asked is a+b+c =7+4+1=12

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VIGNESH  (9 years ago)

in order to obtain the unit digit as 5 we have to multiply the 31 with 5 anh hence 155 then remaining can be obtained 210 by taking value ans is 14

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Krishna Kumar  (9 years ago)

1+4+7=12 a month having 31 days that is 7 and a month having 30 days that is 4 and 1 is feb.

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