Latest Elitmus Aptitude Question SOLUTION: What is the value of x is real number ? (1) x^2 + 1 = 1/(x^2 + 1) (2) x^3 + x^2 = 0 Mark A if question can be answered by using one of the statements alone, but cannot be answered

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(#M40040118) ELITMUS Logical Reasoning question data sufficiency Keep an EYE

What is the value of x is real number ?
(1) x^2 + 1 = 1/(x^2 + 1)
(2) x^3 + x^2 = 0
Mark A if question can be answered by using one of the statements alone, but cannot be answered by usingthe other statements alone
Mark B if question can be answered by using either statements alone
Mark C if question can be answered by using both statements together, but cannot be answered by using either statements alone
Mark D if question can not be answered even by using both statements together

Asked In Elitmus anand mumbai (9 years ago)

Unsolved Read Solution (20)

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Read Solution (20) :

Arjun Singh Baghel  (9 years ago)

Ans = A
from statement 1-
(x^2+1)^2=1
x^2+1=+-1
now x^2+1=1,,,so x=0
and x^2+1=-1,,,,,,so x=(-2)^1/2 (It is not possible )
from statement 2-
x^3+x^2=0
x^2(x+1)=0
so x=0 & -1(both r real )
here value of x is not clear .

so statement-1 is sufcnt

Is this solution Helpfull? Yes (35) | No (10)  

Vivek singh bhatnagar  (9 years ago)

ans is B
both eq can ans alone

Is this solution Helpfull? Yes (24) | No (5)  

Arjun Singh Baghel  (9 years ago)

my solun is right bcz i got marks on this question

Is this solution Helpfull? Yes (7) | No (1)  

kumar  (9 years ago)

since in question they are not asking exact value of x
and here from both equn we can find that value of x are are real
from eq 1-
(x^2+1)^2=1
x^4+2x^2+1-1=0
X^2(x^2+2)=0
either x^2=0, or x^2=-1
since x^2=-1 does not exist, so real value is 0,

Now from eq 2
x^3+x^2=0
X^2(x+1)=0
either x^2=0, or x=-1

hence ans should be b

Is this solution Helpfull? Yes (4) | No (4)  

Gautam Raj  (9 years ago)

B) It can be answered by anyone of the options.

Is this solution Helpfull? Yes (2) | No (1)  

asif shakil  (9 years ago)

statement 1-
x^2+1=1/x^2+1
=>(x^2+1)^2=1
this gives x=0 or x=(-2)^1/2

statement 2-
x^3+x^2=0
=>x^2(x+1)=0
this gives x=0 or x=-1.
so we different solution for the value of x....
therefore ans is (d)....the question cannot be answered by using both d statements.

Is this solution Helpfull? Yes (2) | No (5)  

pranav lohkare  (9 years ago)

b.......
question can b answered by referring both equations alone..

Is this solution Helpfull? Yes (1) | No   

manish kumar sharma  (9 years ago)

(1) x^2+1 = 1/(x^2+1)
(X^2+1)^2 = 1
x^2+1 = +1 or x^2+1 = -1
x^2 = 0 or x^2 = -2 (cant be possible)
x=0.....:)

(2) X^3+X^2= 0
x^2(x+1)= 0
x=0 or x=-1 possible
ans will be (B)

Is this solution Helpfull? Yes (1) | No   

priyanka bhartee  (9 years ago)

both are required

Is this solution Helpfull? Yes | No (2)  

Vinay Jain  (9 years ago)

B
both equations can solve the problem.

Is this solution Helpfull? Yes | No   

chandan  (9 years ago)

from eq 1-
(x^2+1)^2=1
x^4+2x^2+1-1=0
X^2(x^2+2)=0
either x^2=0, or x^2=-1
since x^2=-1 does not exist, so real value is 0,

Now from eq 2
x^3+x^2=0
X^2(x+1)=0
either x^2=0, or x=-1
here both are real.

Is this solution Helpfull? Yes | No   

Pankaj Yadav  (9 years ago)

(x^2+1)^2=1, x^2+1=+-1,x=0 only

Is this solution Helpfull? Yes | No   

sravani  (9 years ago)

Ans is B : x can be solved from either of the statements...

Is this solution Helpfull? Yes | No (1)  

divya  (9 years ago)

B..
using both stmnts we can calculate the value of x

Is this solution Helpfull? Yes | No   

rajveer singh  (8 years ago)

A is the right answer as using 2nd equation answer can not be found............... :P

Is this solution Helpfull? Yes | No   

Abhishek Mohanty  (8 years ago)

Answer is A

Is this solution Helpfull? Yes | No   

kundan prasad  (8 years ago)

Ans: A

Is this solution Helpfull? Yes | No   

utkarsh singh  (8 years ago)

A because using the expression 1 we get imaginary value of x

Is this solution Helpfull? Yes | No   

ROHIT YADAV  (8 years ago)

from 1st we will get x=square root of i that is complex
so alone by 2nd x=-1
hence A

Is this solution Helpfull? Yes | No   

Sanjay Mogra  (8 years ago)

Answer is both statements are needed becoz statement 1 gives 2 solution and statement 2 gives 2 solution . But one solution is common i.e. x=0

Is this solution Helpfull? Yes | No   

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