Latest Elitmus Aptitude Question SOLUTION: (n+a) and (n+b) are the two perfect square , n,a,b are whole numbers. a=11, b=56 so what are the possible values of n...??? i) None ii) only 1 iii) 2 iv) 4

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(#M40040121) ELITMUS Numerical Ability question Arithmetic Keep an EYE

(n+a) and (n+b) are the two perfect square , n,a,b are whole numbers.
a=11, b=56 so what are the possible values of n...???

i) None ii) only 1 iii) 2 iv) 4

Asked In Elitmus Gautam Raj (9 years ago)

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Vivek singh bhatnagar  (9 years ago)

ans is 2
n=25
n=473

Is this solution Helpfull? Yes (29) | No (5)  

Adil khan  (6 years ago)

lets assume n+a=x^2 and n+b=y^2
n=X2-a and n=Y2-b
equate then
y2-x2=56-11=45
(y+x)(y-x)=45
so factors of 45
45*1 and 15*3 and 9*5 =45
y+x=45 y-x=1 then y=23 x=22 then n=529-56=473 and 484-11=473
y+x=15 and y-x=3 then y=9 and x=6 then n=81-56=25 and 36-11= 25
y+x=9 and y-x=5 then y=7 and x=2 the 49-56 not possible and 4-11 not possible so
ans is 473 and 25 only 2

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sourabh baya  (9 years ago)

n=25
only 1

Is this solution Helpfull? Yes (9) | No (9)  

Vivek singh bhatnagar  (9 years ago)

ans is 2
n=25
n=273

Is this solution Helpfull? Yes (8) | No (12)  

pawan   (9 years ago)

ans is 2 only two values n=25 and n=473

Is this solution Helpfull? Yes (5) | No (2)  

Kumar Vikash  (9 years ago)

ans is 2
n=-7
n=25

Is this solution Helpfull? Yes (1) | No (20)  

manish kumar  (9 years ago)

unit digit only depend upon unit digit that is 1 in 101 so 1 to power anything will be 1

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Anuj Awasthi  (9 years ago)

Sry i m anable to answer

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Saddam Anwar Tagala  (9 years ago)

a perfect square is the product of two equal integers
e.g.
9 is a perfect square because it can be expressed as 3 * 3 (the product of two equal integers)

ans is i)none

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ASHISH MUKHERJEE  (9 years ago)

In this question their is no limitation of n like,the the value of n should be less then 200,300 etc.

initially if we will put n=25,473 it satisfied but surely so many other numbers are their which might be satisfy the condition ,since limitation not given .
According to option 1) non of these will be ok.

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