Latest Elitmus Aptitude Question SOLUTION: A number 10,10,101 when multiplied with N gives product P, such that N is any no with only 1 as its digit (eg. N = 11,111,1111,.......) .How many different digit can be possible in

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(#M40040171) ELITMUS Numerical Ability question Number System Keep an EYE

A number 10,10,101 when multiplied with N gives product P, such that N is any no with only 1 as its digit (eg. N = 11,111,1111,.......) .How many different digit can be possible in the product P.

(a) 2
(b) 3
(c) 4
(D) not remembered

Asked In Elitmus Priyabrata Nayak (9 years ago)

Solved Rajat tandon Read Solution (20)

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Read Solution (20) :

Ram  (9 years ago)

N*10*10*101=P
P=N*100*(100+1)
P=10000*N+100*N
suppose if N=11 then P=111100
if N=111 then P=1121100
if N=1111 then P=11221100
and N=11111 then P=112221100
an so P only contains digits such as 0,1,2 with repeatations
so answer is 3 (option b)

Is this solution Helpfull? Yes (72) | No (10)  

Rajat tandon  (9 years ago) Best Solution

ans is 4...coz after multiplying it many times there will come an ans having 4 different digits(1,2,3,4) and when u multiply it again with N having one more 1,then there will be repetation of the digits.

Is this solution Helpfull? Yes (18) | No (12)  

raman sharma  (9 years ago)

N*10*10*101=P
P=N*100*(100+1)
P=10000*N+100*N
suppose if N=11 then P=111100
if N=111 then P=1121100
if N=1111 then P=11221100
an so P only contains digits such as 0,1,2 with repeatations
so answer is 3

Is this solution Helpfull? Yes (10) | No (3)  

Vijay Kant  (9 years ago)

answer will be 9

Is this solution Helpfull? Yes (9) | No (7)  

victor munna  (9 years ago)

if number is 1010101 then ans is 4(1,2,3,4)
if number is 10,10,101 then ans is 3(0,1,2)

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Bhvin Sanchiher  (9 years ago)

answer will be 4... 0,1,2,3...if u are in doubt...just multiply it with 11111 and see for yourself if u get 3 or not

Is this solution Helpfull? Yes (2) | No (1)  

Goldy Shukla  (9 years ago)

answer will be 3 and digits are 1,2,3.

Is this solution Helpfull? Yes (1) | No (3)  

Goldy Shukla  (9 years ago)

vijay could you please explain how it would be 9?

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Vijay Kant  (9 years ago)

take N= 11111111111

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suraj kumar shukla  (9 years ago)

@Ram gud one bro .. 0,1,2 is correct

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Yash Puri  (9 years ago)

ans is 4 bcoz o multiplying with largest possible 1111111 we got com of 4 digits

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ASHUTOSH KUMAR  (9 years ago)

ans will be 2 because u can multipli with N to any no among the three u will always get either 1 or 2 differnt digit
ex:- 111111111*101=22222222211

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surbhi dubey  (9 years ago)

2 diff no....i.e 0,1

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ayush  (9 years ago)

hh explain

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ANANT VIKRAM SINGH  (9 years ago)

@rajat only 0,1,2 are repeated so how the answer is 4 instead of 3 pls explain.

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Raashid khan  (9 years ago)

at most 3...start multiplying 1010101 with 1 as unit digit, then 11, 111 you will see the pattern that atmost 3 different digits are possible in P

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sumit kumawat  (9 years ago)

N*10*10*101=P
P=N*100*(100+1)
P=10000*N+100*N
suppose if N=11 then P=111100
if N=111 then P=1121100
if N=1111 then P=11221100
an so P only contains digits such as 0,1,2 with repeatations
so answer is 3
Read more at http://www.m4maths.com/placement-puzzles.php?ISSOLVED=&page=2&LPP=10&SOURCE=Elitmus&MYPUZZLE=&UID=&TOPIC=Numerical%20Ability&SUB_TOPIC=Number%20System#hFd5u7T02MPjt111.99

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Suyash  (9 years ago)

10 digits are possible 0 to 9.
Furthermore, the multiplication gives a pallindrome.

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Chirag Ranjan Lahiri  (9 years ago)

10 digits are possible 0 to 9.

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shilpa  (7 years ago)

3 becoz digits are (0,1,2)

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