Latest Elitmus Aptitude Question SOLUTION: a and b are natural number , Is a>b?? a) 8-(a-b)^3 is positive b) 4-(a-b)^2 is negative

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(#M40040372) ELITMUS Logical Reasoning question data sufficiency Keep an EYE

a and b are natural number , Is a>b??
a) 8-(a-b)^3 is positive
b) 4-(a-b)^2 is negative

Asked In Elitmus kumar (9 years ago)

Unsolved Read Solution (21)

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Read Solution (21) :

praveen kumar  (9 years ago)

No one alone can satisfy the equation .. Even both equation together are also insufficient to satisfy the equation..

Is this solution Helpfull? Yes (24) | No   

kumar  (9 years ago)

@ Ankit sukla
take a=-4 < b=2
8-(-4-2)^3=8+36*6=+ve ,then how a
i am sure no one alone can satisfy , ? about both together

Is this solution Helpfull? Yes (6) | No   

Durgesh Kumar  (9 years ago)

both are insufficient

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ankit shukla  (9 years ago)

a is answer

Is this solution Helpfull? Yes (3) | No (2)  

Kumar Vikash  (9 years ago)

both equation are required to find a>b.

Is this solution Helpfull? Yes (2) | No (7)  

Durgesh Kumar  (9 years ago)

a) 8-(a-b)^3>0 b) 4-(a-b)^2(a-b)^3 or +/- 2

Is this solution Helpfull? Yes (1) | No   

Kumar Vikash  (9 years ago)

both equation are required to find a>b. my score has been released and my ans was correct...maine four kia the ps me and all four are correct and one of the correct ans is this...

Is this solution Helpfull? Yes (1) | No (3)  

archana kumari  (9 years ago)

I think we only have to find that a>b is right or wrong..nd we can find this from statement A..answer should be one..

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NURAG  (9 years ago)

8-(a-b)^3>0..............(i){this alone can’t answer for example a=4,b=1}

4-(a-b)^20..............(iii)

inequality (ii)==inequlity(iii)
Now inequlity (i)+(iii)

8-(a-b)^3+(a-b)^2-4 >0

(a-b)^2*(1-a+b)+4>0{Now addition of both also can’t answer take a=4,b=1}

So we cant answer even we take both the statement

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kumar  (9 years ago)

sorry @ankit sukla
take a=1 < b=2

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shekhar  (9 years ago)

from a) we get a-b

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srinu  (9 years ago)

only a is sufficient

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RAVI KUMAR  (9 years ago)

(a)i think if a=5 and b=10 then a

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pankaj narayan  (9 years ago)

(a-b)^2 > 4
so (a-b)^3 is definitely > 8
(a-b)^3 is negative , as final result is positive.
So, (a-b) is negative.
a is not greater than b , a

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Arun Kumar  (9 years ago)

a-b>0
t=a-b
t^34
assume t=+-2.1
then t =-2.1 would satisfy 1st eq but that would mean ta

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prem  (9 years ago)

both aand b are insufficent to satisfy the relation...

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sravani  (9 years ago)

either of the statements leads to a solution...

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HARSHA   (9 years ago)

8-(a-b)^3 > 0 (because positive) 4-(a-b)^2 < 0 (because -ve)
then 8> (a-b)^3 2^2 a-b

so we cant say 2 is either less or greater than a-b so we cant say a>b

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Tarun Sharma  (8 years ago)

from(a) (a-b)

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ANURAG ANAND  (8 years ago)

both are insufficient to answer the question. as no statement can provide the unique vale of a and b.

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nidhi tiwari  (8 years ago)

here both statement alone can satisfy the equation
solution:
a)8-(a-b)^3>0
8>(a-b)^3
2>(a-b)
b+2>a
because a ,b are natural no so from here we find that a>b or not
so it is alone sufficient

b) 4-(a-b)^2

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