Latest Elitmus Aptitude Question SOLUTION: A number p is 3 digit number like 1st digit is square of last digit. and no digit is same . so how many p is possible which is divisible by 3 .

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Number System

Elitmus Question Papers:

(#M40040669) ELITMUS Numerical Ability question Keep an EYE

A number p is 3 digit number like 1st digit is square of last digit. and no digit is same . so how many p is possible which is divisible by 3 .

Asked In Elitmus DEEPAK SONI (9 years ago)

Unsolved Read Solution (30)

Is this Puzzle helpful?   (15)   (2) Submit Your Solution Number System

Read Solution (30) :

Goldy Shukla  (9 years ago)

Three digit number = xyz
Rule1: 1st digit is square of last = x^2yx

Only numbers and their square are in single digit= 2,3 and their square are 4&9.

possible numbers:
4y2=402,412,432,452,462,472,482,492
9y3=903,913,923,943,953,963,973,983

Rule2: Number should be divisible by 3.
Now all possible numbers are:
4y2/3=402,432,462,492 = 4 count
9y3/3=903,963 = 2 count

hence total number count is 4+2=6.

Is this solution Helpfull? Yes (85) | No (3)  

Vijay Menaria  (9 years ago)

total 6
903
963
402
432
462
492

Is this solution Helpfull? Yes (24) | No   

rashmi  (9 years ago)

i dont think unit digit squares are only 2 & 3 even 1 have.(0,1,2,3,4,5,6,7,8,9)
1^2=111,141,171 which is 3 digit div by 3
2^2=402,432,462,492 which is div by 3
3^2=903,933,963,993
so total=11

Is this solution Helpfull? Yes (10) | No (27)  

MD AQUIL AKHTAR  (9 years ago)

This is not for E-litmus level question.

Is this solution Helpfull? Yes (5) | No (4)  

Sujata Sinha  (9 years ago)

The three digit number is of the form a^2ba.
Now the numbers in the units digit can be (1,2,3) and in tens place can be (1,4,9) respectively.
Now when in units place 1 is there we get: 111, 141, 171 which are divisible by 3.
Now when in units place 2 is there we get: 402, 432, 462, 492 which are all divisible by 3.
Now when in units place 3 is there we get: 903, 933, 963, 993 which are again all divisible by 3.

Hence total of 11 numbers..

Is this solution Helpfull? Yes (4) | No (5)  

Tejesh Agrawal  (9 years ago)

ans. 6
913
923
943
953
973
983

Is this solution Helpfull? Yes (2) | No (9)  

ranju kumari  (9 years ago)

only 2 posible no. can take 1st position ie- 2 and 3with last digit being 4&9.

now to find the middle no combination, we know that for a no. divisible by 3.. sum of digit shud be divisible by 3.
So, 2+6 & 3+9 are already divisible by 3.
Now middle digit can be 0,3,6,9...
ie, no are 402,432,462,492,903,963.

so ans is 6

Is this solution Helpfull? Yes (2) | No   

AMIT ANAND  (9 years ago)

total 8
903
933
993
963
402
432
462
492

Is this solution Helpfull? Yes (2) | No (18)  

kamini kaushik  (9 years ago)

there are 3 possibilities for last digit.....
which is 1,2,3..
for digit 1.. 111,141,171...total 3 numbers..
for digit 2....402,432,462,492...total 4 numbers..
for digit 3..903,933,963,993...total 4 numbers..
answer is =3+4+4=11

Is this solution Helpfull? Yes (2) | No (2)  

sanjana  (9 years ago)

ans . 6
903
923
432
462
492
936
943

Is this solution Helpfull? Yes (1) | No (6)  

ravi prakash  (9 years ago)

only 6 no is possible
4m2,9n3
this is general no format sum of these no 4+m+2 will be divisible by 3
similarly others no
so only 402,432,462,492
903,963

Is this solution Helpfull? Yes (1) | No   

dipti  (9 years ago)

answer is 6

Is this solution Helpfull? Yes (1) | No   

Rahul Prakash Gupta  (9 years ago)

The answer will be 11.
condition 1: 1st digit is square of last digit.
The possible 1st and last digit combination will be : 1st-1, last-1
1st-4, last-2
1st-9, last-3
condition 2: The number should divisible by 3.
Therefore, for 1st=1 and last=1, the possible number will be- 111, 141, 171.

for 1st=4 and last=2, the possible number will be- 402, 432, 462, 492.

for 1st=4 and last=2, the possible number will be- 903, 933, 963, 993.
Hence total number of combination will be: 3+4+4=9.

Is this solution Helpfull? Yes (1) | No (5)  

Amey Kakirde  (9 years ago)

Ans 5
432
462
492
903
963

Is this solution Helpfull? Yes | No (5)  

minupala swathi  (9 years ago)

804,834,864,894 can also satisfy

Is this solution Helpfull? Yes | No (11)  

Pranshu Preet Kaur  (9 years ago)

ans is 6

4_2
9_3
are the possibilities.....( 402,432,462,492
903,963 )

Is this solution Helpfull? Yes | No   

Anjana Kumari  (9 years ago)

ans is 6
903, 963,402,432,462,492

Is this solution Helpfull? Yes | No   

Shio Shanker Awasthi  (9 years ago)

The correct answer is 6
let the number P=xyz
1st it is said that=z^2yz
Only numbers and their square are in single digit =1,2,3 and their square are 1,4,9
we will not take 1 as in question it is said that no digit is same.

Possible value:
2^2y2=402,,432,462,492 =4

3^2y2 =903,963=2
so total numbers are 6.

Is this solution Helpfull? Yes | No   

Manisha Barik  (9 years ago)

Total is 8....
402,432,462,492
903,933,963,993

Is this solution Helpfull? Yes | No (1)  

BARUN KUMAR  (9 years ago)

11
111,141,171
402,462,432,492
90,933,963,993

Is this solution Helpfull? Yes | No   

swati priya  (9 years ago)

3 ways for no 4 _ 2 and 4 ways for 9 _ 3 which is divisible by 3. so,
total of 3+4 = 7 ways and 7 possible no is there with non repeating three digit no.

Is this solution Helpfull? Yes | No   

vikas kumar  (9 years ago)

6
402
432
462
492
903
963

Is this solution Helpfull? Yes | No   

ASHISH MUKHERJEE  (9 years ago)

possible numbers are:- 402,432,462,492,903,963,
so total no can be possible only :- 6.

Is this solution Helpfull? Yes | No   

Rahul Ranjan  (9 years ago)

Rashmi or minupala boki h...

Is this solution Helpfull? Yes | No   

Kamlesh Kumar  (9 years ago)

402
432
462
492
903
963

Is this solution Helpfull? Yes | No   

Prakhar Kumar  (9 years ago)

903
963
402
432
462
492
Total no of p=6

Is this solution Helpfull? Yes | No   

DANISH BILAL  (9 years ago)

No digit should be same..
4_2 :- 402,432,462,492..total 4
9_3 :- 903,963.. total 2
total number is 6

Is this solution Helpfull? Yes | No   

PRABHAKAR KUMAR  (9 years ago)

right answer 8 number
402
432
462
493
903
933
963
993
and 111 not including because in question say no digit are same

Is this solution Helpfull? Yes | No   

marjita chakraborty  (8 years ago)

1^1=1(rejected.since the numbers in the digits cannot repeat itself according to the question)
2^2=4
3^2=9
so the 3 digit numbers will be- 4y2 & 9y3
check y=0,1,2....9 and check the numbers divisibility by 3 such that every digit in the 3 digit number is unique
the numbers divisible by 3 are: 402,432,462,492,903,963 are the required numbers.

Is this solution Helpfull? Yes | No   

RAJNISH SINGH  (8 years ago)

402,432,462,492,903,963=6 numbers

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.